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astra-53 [7]
3 years ago
11

Josh is going to the store to buy candy. Bags of candy corn cost $3 and bags of chocolate cost $5. He needs to buy at least 20 b

ags of candy and he cannot spend more than $60. Write a system of linear inequalities to model the situation.
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

x + y ≥ 20

3x + 5y > 60

Step-by-step explanation:

Let

Bags of candy corn = x

Bags of chocolate = y

Cost of bags of candy corn = $3

Cost of bags of chocolate = $5

He needs to buy at least 20 bags of candy and he cannot spend more than $60

system of linear inequalities to model the situation.

x + y ≥ 20

3x + 5y > 60

The system ot inequalities which models the situation

x + y ≥ 20

3x + 5y > 60

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PLEASE HELP FAST!! WILL MARK BRAINLIEST!!!!
Aleonysh [2.5K]
In 4 days Bryn sells 24 tickets (50-26)
So in 1 day he sells 6 tickets --> B is right
The +33 in the equation means, that Eddie sold 33 tickets oon the first day
--> So C.) and D.) are right
When you replace the x in the equation with 1, you'll get the tickets, that eddie sold on the first day. --> y = 5 *(1)+33 = 38
38 tickets - 33tickets = 5 tickets ( the rise)
-->A.) is wrong, because Bryn sold two tickets more as Eddie per day

4 0
3 years ago
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Solve the equation.<br><br> 3(x−9)=30
a_sh-v [17]

Answer:

x = 19

Step-by-step explanation:

3(x - 9) = 30

Divide both sides by 3 to isolate the binomial.

x - 9 = 10

Add 9 to both sides to isolate x.

x = 19

Check your answer by plugging x = 19 back into the equation.

3(x - 9) = 30

3(19 - 9) = 30

Subtract.

3(10) = 30

Multiply.

30 = 30

Your answer is correct.

Hope this helps!

3 0
3 years ago
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I need to know how to solve this problem because I’m very confused and it doesn’t explain what it is or how to do it in my textb
Lostsunrise [7]

Answer:

x1 = -4; x2 = 10

Step-by-step explanation:

1) Expand the module as two separate equations:

x - 3 = 7

x - 3 = -7

2) Solve the equations:

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x = -4

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5 0
3 years ago
G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =
laiz [17]

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

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h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

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Andreas93 [3]

Answer:

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Step-by-step explanation:

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3 years ago
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