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3 years ago

13

If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?

1 answer:

SVEN [57.7K]3 years ago

7 0

(g-f)(x)=g(x)=f(x)

(g-f)(x)=6x-4+x^2

(g-f)(x)=x^2+6x-4 then:

(g-f)(3)=3^2+6*3-4

(g-f)(3)=9+18-4

(g-f)(x)=23

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To solve this problem you must apply the proccedure shown below:

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3 years ago

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What is the answer of this problem if mr.reyes gave his daughter P250 on her 18th birthday and intends to increase this by P150

o-na [289]

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3 years ago

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What is 3.3(x-8)-x=1.2

11Alexandr11 [23.1K]

Multiply 3.3 by everything in the parenthesis.

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2 years ago

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Please help fassssst

Zarrin [17]

Answer:

$\dfrac{9}{2}$

Step-by-step explanation:

You can do this using the quadratic equation:

$x =\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

Let's first setup our expression:

4x² + 12x = 135

the quadratic formula is:

ax² + bx + c = 0

4x² + 12x - 135 = 0

Then:

a = 4

b = 12

c = -135

Now we plug in our coefficients and solve:

$x =\dfrac{-12\pm\sqrt{12^{2}-4(4)(-135)}}{2(4)}$

We solve for both to determine the positive one:

$x =\dfrac{-12+ \sqrt{12^{2}-4(4)(-135)}}{2(4)}$ $x =\dfrac{-12- \sqrt{12^{2}-4(4)(-135)}}{2(4)}$

$x =\dfrac{-12+ \sqrt{144+2160}}{8}$ $x =\dfrac{-12- \sqrt{144+2160}}{8}$

$x =\dfrac{-12+ \sqrt{2304}}{8}$ $x =\dfrac{-12- \sqrt{2304}}{8}$

$x =\dfrac{-12+ 48}{8}$ $x =\dfrac{-12- 48}{8}$

$x =\dfrac{36}{8} = \dfrac{9}{2}$ $x =\dfrac{-60}{8} = \dfrac{-15}{2}$

So if you are looking for a positive solution, just take the positive one as x.

8 0

2 years ago