Question

A scooter was bought at Rs 42,000. its value depreciated at the rate of 8% per annum. find its value after one year​

Answer 1

Answer:

Rs 38,640

Step-by-step explanation:

Pay attention:

$A = P(1+r/100)^n$

The principle (p) : Rs 42,000

Rate of interest (r) : 8%

Time (n) : 1 years

Exact Amount (a) : P(1-R/100)^n

Value:

A = 42,000(1 - 8/100)^1

A = 42,000(1 - 2/25)

A = (42,000 * 23)/25

A = 1,680 * 23

A = Rs 38,640