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Nataliya [291]
3 years ago
10

A pool cover is 25 feet by 50 feet. What is its square area in meters?

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
8 0

Answer:

1250 m^2

Step-by-step explanation:

Area = 25 * 50 = 1250 m^2

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What is the solution to this system of linear equations 3x 2y 14 5x y 32
Leya [2.2K]

After simplification, the solution of this system of linear equation is (3.85, 12.75).

In the given question we have to find the solution to this system of linear equations 3x-2y=14 or 5x+y=32.

The given system of linear equations is:

3x-2y=14.......................(1)

5x+y=32.......................(2)

Multiply equation 2 by 2, we get

10x+2y=64.......................(3)

Add equation 3 by 1, we get

10x+2y+3x-2y=64-14

13x=50

Divide by 13 on both side, we get

x=3.85

Now put the value of x in equation 2

5(3.85)+y=32

19.25+y=32

Subtract 19.25 on both side, we get

y=12.75

So, the solution of this system of equation is (3.85, 12.75).

To learn more about system of linear equation link is here

brainly.com/question/27664510

#SPJ4

6 0
2 years ago
Solve this identifying holes, vertical asymptotes, and horizontal asymptotes for
USPshnik [31]

x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}

\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}

6 0
4 years ago
At what point does the curve have maximum curvature? y = 9 ln(x) (x, y) =
Andrews [41]

y = 9ln(x) 
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2

curvature k = |y''| / (1 + (y')^2)^(3/2) 

<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2) 
= (9/x^2) / (1 + 81/x^2)^(3/2) 
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)] 
= 9x(x^2 + 81)^(-3/2). 

To maximize the curvature, </span>

we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2) 
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2] 
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2) 

Setting k' = 0 yields x = ±9/√2. 

Since k' < 0 for x < -9/√2 and k' > 0 for x > -9/√2 (and less than 9/√2), 
we have a minimum at x = -9/√2. 

Since k' > 0 for x < 9/√2 (and greater than 9/√2) and k' < 0 for x > 9/√2, 
we have a maximum at x = 9/√2. </span>

x=9/√2=6.36

<span>y=9 ln(x)=9ln(6.36)=16.66</span>  

the answer is
(x,y)=(6.36,16.66)
7 0
4 years ago
Find the length of the third side of the right triangle. Give an exact answer and an approximation to three decimal places if ne
trasher [3.6K]

Answer:

a = 32

Step-by-step explanation:

This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths

68^2 = 60^2 + a^2

4624 = 3600 + a^2

4624 - 3600 = a^2

1024 = a^2 find the root for both sides

32 = a

8 0
3 years ago
64000 / blank equals 800
Irina18 [472]

Answer:

= 80

Step-by-step explanation:

64000/80 = 80

3 0
3 years ago
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