The answer is -4,0 4,8 because u would solve for one variable in one of the equations and then substitute the result into the other
Answer:
57
Step-by-step explanation:
It is given in the question that length CDA = 57.
Since the shape is a parallelogram, then we know that length AD=BC and AB=CD.
CDA = CD + AD
BCD = BC + CD
Since BC=AD and CD=CD
BCD = BC + CD is the same as CD + AD = CDA
Therefore BCD is the same length as CDA = 57
In other words, CDA is made up of a long side and a short side = 57
BCD is also made up of a long side and a short side, and since the longs sides are equal to each other and the short sides are also equal to each other in a parallelogram, BCD is the same length as CDA = 57.
Hope this helped!
Answer: H is 5 and K is 2
Step-by-step explanation:
Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
