Question

Please help out would really appreciate it

Answer 1

Answer:

Step-by-step explanation:

1. Apply the Pythagoras theorem to determine the value of x, we have;

$/Hyp/^{2}$ = $/Adj 1/^{2}$ + $/Adj 2/^{2}$

$x^{2}$ = $15^{2}$ + $8^{2}$

   = 289

x = $\sqrt{289}$

x = 17

2. Trigonometric ratios of <D.

i. Sin <D = $\frac{opposite}{hypotenuse}$

              =  $\frac{8}{17}$

ii. Cos <D = $\frac{Adjacent}{Hypotenuse}$

                = $\frac{15}{17}$

iii. Tan <D = $\frac{Opposite}{Adjacent}$

                 = $\frac{8}{15}$

3. Trigonometric ratios of <F.

i. Sin <F = $\frac{opposite}{hypotenuse}$

             = $\frac{15}{17}$

ii. Cos <F = $\frac{Adjacent}{Hypotenuse}$

              =  $\frac{8}{17}$

iii. Tan <F = $\frac{Opposite}{Adjacent}$

               = $\frac{15}{8}$