Question

Write an equation of a line that passes through the point (7,3) and is parallel to the line y=-2/3x+3

Answer 1

Its a motha "A" dude

Answer 2

Answer:
y = -2/3 x + 23/3

Explanation:
The general formula of the linear equation is:
y = mx + c
where:
m is the slope
c is the y-intercept

1- getting the slope:
We are given that the line we are looking for is parallel to the line
y = -2/3 x + 3
This means that the slope of the two lines are equal. Comparing the general formula with the given line, we would find that the slope of the given line is -2/3. This means that the slope of the line we are looking for is also -2/3
The equation of the line now becomes:
y = -2/3 x + c

2- getting the value of c:
To get the value of c, we will use a point that belongs to the line (7,3), substitute in the equation and solve for c as follows:
y = -2/3 x + c
3 = (-2/3)(7) + c
3 = -14/3 + c
c = 3 + 14/3
c = 23/3

Based on the above, the equation of the line we are looking for is:
y = -2/3 x + 23/3

Hope this helps :)