Probability of rolling a 6 with two dice one with values 1, 2, 2, 3, 3, 4 and 1, 3, 4, 5, 6, 8
777dan777 [17]
Answer:
11/12 chance of the probability of rolling a 6 with 2 dice
Set up two equations.
s + 12 = l , s + l = 74 (these equations represent the problem)
s + (s + 12) = 74 plug in "l" to the second equation.
2s + 12 = 74 combine like terms.
2s + 12 - 12 = 74 - 12 subtract to isolate the variable
2/2s = 62/2 divide to isolate the variable.
s = 31. This means the smaller number is 31.
31 + 12 = 43. since the larger number is 12 more than the smaller, add 12.
l = 43 the larger number has a value of 43.
small number = 31
larger number = 43
hope this helps! :D
Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p
a. 1/2
b. 2 times
c. 1/4
d. 4 times
Answer:
4 times
Step-by-step explanation:
Given the following :
Distance between q and S (r) = 1 unit
Distance between P and S (r) = 2 × 1 unit = 2
According to coliumbs law:
F = Ke(q1q2) /r^2
Where F = electrostatic force, Ke = coloumbs constant
q1,q2 = charges, r = distance between two charges
For q and S :
Fsq = Ke(q1q2) / 1^2
Fsq = Ke(q1q2) - - - - - equation 1
For P and S :
Fsp = Ke(q1q2) / 2^2
Fsp = Ke(q1q2) / 4 - - - - - equation 2
Dibiding equation 1 by equation 2
Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4
Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)
Fsq / Fsp = 4 / 1
Using cross multiplication
Therefore, Fsq = 4 × Fsp
40 sets of tires. I learned this by looking up your question because it is incomplete.
20 golf balls can fit in the can.
<u>Step-by-step explanation:</u>
Given:
Height (h) = 10 Inches
Volume of 15.625 Pi inches cube.
To Find:
How many balls can be filled in that can.
Solution:
Diameter of the golf ball [as per standard value] = 1.68 in
Radius of the golf ball = 
Volume of the golf ball = 
=
=
Volume of the can = 
Now we have to divide the volume of the can by the volume of the golf ball, we will get =
balls
Thus we can conclude that approximately 20 balls can be filled in that can.