1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
S_A_V [24]
3 years ago
12

Solve -6 4/9-3 2/9-82/9

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0

Answer: The final answer in proper fraction is 169/9

Step-by-step explanation:

Given the expression

-6 4/9-3 2/9-82/9

Firstly let us convert all mixed fraction to proper fraction to further simplify the expression

-58/9 - 29/9 - 82/9

We now have all terms in proper fraction, we can continue by finding the LCM which is 9

= (- 58-29-82)/9

= 169/9

You might be interested in
A bathtub contains 20 gallons of water. After the drain is opened, there are 14 gallons of water remaining after 30 seconds. Usi
leva [86]

Answer

a decrease of 0.2 gallons per second

Explanation

The drain was open for 30 seconds.

The water that ran out for 30 seconds = 20 - 14

= 6 gallons

Rate of decrease = (change in gallons)/(time taken)

= 6/30

= 0.2

The rate of change in the amount of water remaining in the tub per second will be the same as the one that ran out since the outlet is the same.

So the correct answer from the choices is "a decrease of 0.2 gallons per second".

7 0
3 years ago
1.Find the compound interest on Rs25000 for 3 years at 10% per annum ,Compounded annually.
LekaFEV [45]

Answer:

The compound interest is Rs8275

Step-by-step explanation:

The rule of the compound interest is A = P(1+\frac{r}{n})^{nr}, where

  • A is the new amount
  • P is the initial amount
  • r is the interest rate in decimal
  • n is the number of periods
  • t is the time

The interest I = A - P

∵ The amount of investment is Rs25000 for 3 years

∴ P = 25000

∴ t = 3

∵ The rate of interest is 10% per annum, compounded annually

∴ r = 10% = 10 ÷ 100 = 0.1

∴ n = 1 ⇒ compounded annually

→ Substitute these value in the 1st rule above to find the new amount

∵ A = 25000(1+\frac{0.1}{1})^{1(3)}

∴ A = 25000(1.1)^{3}

∴ A = Rs33275

→ Use the 2nd rule above to find the interest

∵ I = 33275 - 25000

∴ I = 8275

∴ The compound interest is Rs8275

6 0
2 years ago
What is the reflection of an object referred to? post-image image transformation pre-image
xz_007 [3.2K]

Answer: image transformations

Step-by-step explanation:

5 0
3 years ago
535.29 = 400(1 + r) 5
joja [24]

Answer:

Step-by-step explanation:

(1+r)^5=\frac{535.29}{400} \\1+r=(\frac{535.29}{400}) ^{\frac{1}{5} } \\1+r \approx 1.06\\r \approx .06

7 0
3 years ago
12,-12x,12x Like terms
Andrew [12]

Answer:

12

Step-by-step explanation:

Combine like terms *-12x and 12x*

-12x and 12x cancel each other out, therefore your x is gone.

That being said, your answer is 12.

4 0
3 years ago
Other questions:
  • How many 1-inch cubes do you need to create a cube with an edge length of 5 inches?
    14·2 answers
  • Which graph represents the function on the interval [-3,3] <br> F(x)=[x]-2
    5·1 answer
  • Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
    11·1 answer
  • Write the equation of the parabola in vertex form.vertex (0,2), point (1,-5)
    9·2 answers
  • Malloy solved the equation −5x − 16 = 8; his work is shown below. Identify the error and where it was made. −5x − 16 = 8 Step 1:
    14·2 answers
  • Classify if this number is real irrational rational integer whole and natural. Square root of 25/100
    5·1 answer
  • Given a circle with a diameter of 4, which equation expresses pi as the ratio of the circumference of a circle to its diameter
    13·1 answer
  • The triangle pictured below represents a community garden, which is surrounded on
    13·2 answers
  • The picture shows a collection of eight
    7·1 answer
  • PLSS NOBODY WILL HELP ME LATLY PLSS JUST HELP!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!