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Alex Ar [27]
3 years ago
6

Which lists the elements in order from most conductive to least conductive?

Chemistry
2 answers:
garik1379 [7]3 years ago
4 0

Answer:

d

Explanation:

potassium is a metal, germanium is a metalloid, and selenium is a nonmetal.

Zinaida [17]3 years ago
4 0

Answer:

D.potassium (K), germanium (Ge), selenium (Se)

Explanation:

Edgenuity

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The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.
Rzqust [24]

Answer:

Order of the cycle:

Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.

Explanation:

<u>Step -1:</u>

Carbon dioxide is taken in by plants during photosynthesis.

<u>Step -4;</u>

The animal eats a plant and uses its carbohydrates for energy.

<u>Step - 3</u>

The animal releases the carbon dioxide back into the atmosphere during respiration.

<u>Step -2</u>

The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.

Therefore, order of the cycle is Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.

5 0
3 years ago
Read 2 more answers
How much energy must a 10 gram block of ice gain in order to melt ?
Minchanka [31]

Answer:

the answer is 10 times

Explanation:

because it takes 10 times as much energy -3330 j - to melt 10.0 grams of ice.

8 0
2 years ago
Open Ended
kakasveta [241]

Answer:

Explanation:

21. Atoms are not created or destroyed means that atoms that you begin with are the atoms that you will end with. The catch is that the atoms will rearrange to give you new compounds, but the atoms that you initially had are the atoms you will still have after reaction. For eg, if you started with eggs and made omelet. Omelet is a "new" compound, but the atoms that were in the eggs have rearranged to become the omelet so can you see that atoms were not created or destroyed to make the omelet.

22. Yes because amount of products you make depends on how much reactants you have. For eg, I need two graham cracker(GC), one marshmallow(M), and one chocolate (C) to make a s'more. If I get more of each item then I can make more s'mores and consequently having minimum amounts results in less s'mores that I make.

23. Not possible, due to law of conservation of matter and energy. Atoms cannot be created nor be destroyed, they are simply rearranged. For eg, Taking A + B cannot give you a new compound with a chemical formula D or XZ. A + B can however give you AB which is rearrangement of the starting atoms.

24. Chemical equation is balanced when atoms on reactant side and atoms of product side are in equal counts. I have attached a graphic below for more help.

4 0
3 years ago
A 33.0 mL sample of 1.15 M KBr and a 59.0 mL sample of 0.660 M KBr are mixed. The solution is then heated to evaporate water unt
Oksi-84 [34.3K]

Answer:

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

Explanation:

<u>Step 1:</u> Data given

Sample 1: The 1.15 M sample  has a volume of 33.O mL

Sample 2: The 0.660 M sample has a volume of 59.0 mL

Molar mass of KBr = 119 g/mol

Molar mass of AgNO3 = 169.87 g/mol

<u>Step 2:</u> Calculate number of moles for both samples

Number of moles = Molarity * Volume

Sample 1:  1.15 M * 33 *10^-3 L = 0.03795 moles

Sample 2: 0.660 M *59*10^-3 L = 0.03894 moles

Total mol KBr = 0.03795 + 0.03894 = 0.07689 moles

<u>Step 3:</u> Calculate total mass

mass = Number of moles * Molar mass

mass = 0.07689 moles * 119 g/moles = 9.15 grams  ( in 55mL)

<u>Step 4</u>: Calculate moles of AgBr

AgNO3 reacts with KBr  

KBr(aq) + AgNO3(aq) → AgBr(s) + KNO3(aq)

1 mole of KBr consumed, needs 1 mole of AgNO3 to produce 1 mole of AgBr and 1 mole of KNO3

So 0.07689 moles of KBr wll need 0.07689 moles of AgNO3

<u>Step 5:</u> Calculate mass of silver nitrate

mass of AgNO3 = Moles of AgNO3 * Molar mass of AgNO3

mass of AgNO3 = 0.07689 moles * 169.87 g/mol = 13.06 grams

We need 13.06 grams of silver nitrate to precipitate out silver bromide in the final solution

8 0
3 years ago
Can anyone draw a diagram of a liebigs condenser
MrMuchimi

I googled it, here it is lol

6 0
2 years ago
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