Answer:
2Mg^+ +O2 right arrow 2MgO
Explanation:
The mole fraction of KBr in the solution is 0.0001
<h3>How to determine the mole of water</h3>
We'll begin by calculating the mass of the water. This can be obtained as follow:
- Volume of water = 0.4 L = 0.4 × 1000 = 400 mL
- Density of water = 1 g/mL
- Mass of water =?
Density = mass / volume
1 = Mass of water / 400
Croiss multiply
Mass of water = 1 × 400
Mass of water = 400 g
Finally, we shall determine the mole of the water
- Mass of water = 400 g
- Molar mass of water = 18.02 g/mol
- Mole of water = ?
Mole = mass / molar mass
Mole of water = 400 / 18.02
Mole of water = 22.2 moles
<h3>How to de terminethe mole of KBr</h3>
- Mass of KBr = 0.3 g
- Molar mass of KBr = 119 g/mol
- Mole of KBr = ?
Mole = mass / molar mass
Mole of KBr = 0.3 / 119
Mole of KBr = 0.0025 mole
<h3>How to determine the mole fraction of KBr</h3>
- Mole of KBr = 0.0025 mole
- Mole of water = 22.2 moles
- Total mole = 0.0025 + 22.2 = 22.2025 moles
- Mole fraction of KBr =?
Mole fraction = mole / total mole
Mole fraction of KBr = 0.0025 / 22.2025
Mole fraction of KBr = 0.0001
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Answer:
Please find the structure attached as an image
Explanation:
Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.
- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.
- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).
N.B: In the structure attached below, the counting is from the left to right (→).
The percentage yield of the new production technique is 82.8%
<h3>What is the percentage yield?</h3>
Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.
We are told in the question that there are three shifts;
Shift 1 produces 4562 grams
Shift 2 produces 5783 grams
Shift 3 produces 5247 grams
Average production from the three shifts = 4562 grams + 5783 grams + 5247 grams/3 = 5197 grams
The theoretical average yield is = 7000 grams + 7000 grams + 7000 grams/3 = 7000 grams
Now the percentage yield = actual yield/ theoretical yield * 100/1
percentage yield = 5197 grams/7000 grams * 100/1
percentage yield = 82.8%
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