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siniylev [52]
3 years ago
9

I

Chemistry
1 answer:
Damm [24]3 years ago
3 0

Answer: the answer is 18

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3 years ago
Calculate the boiling point of water if the atmospheric pressure is 630 mmhg
Mumz [18]

The boiling point of water can be calculated by the equation:

Where:

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Po = Atmospheric pressure in mm Hg

ΔH= heat of vaporization in kJ/mol

R = Ideal Gas Constant (J/mol-K)

To = normal boiling point in Kelvin

T = boiling point of water (K)

Our known values are:

P = 630 mm Hg

Po = 760 mm Hg

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R = 8.314 J mol⁻¹ K ⁻¹

To = 373 K

Putting these values in the equation,

ln \frac{P_{0}}{P}= \frac{\Delta H}{R}(\frac{1}{T}-\frac{1}{T_{0}})

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Solving the equation will give:

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4 years ago
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