I

A professional technician maintains and operates specialized scientific equipment true or false

tino4ka555 [31]

True for both academic and industrial environments.

4 0

3 years ago

If n=7 and l=6, What are the values of l?

SpyIntel [72]

Wecfifjfjoeoddkcmfkfofofif

7 0

3 years ago

5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a

max2010maxim [7]

Answer: The empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.364g$

Mass of $H_2O=0.0596g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, $\frac{12}{44}\times 0.364=0.0993g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, $\frac{2}{18}\times 0.0596=0.0067g$ of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles$ ]

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = $\frac{0.00828}{0.0067}=1.23\approx 1$

For Hydrogen = $\frac{0.0067}{0.0067}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

$n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}$

The general formula of an alkane is $C_nH_{(2n+2)}$ , where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and $C_{10}H_{10}$ and it is not an alkane.

7 0

4 years ago

An ideal gas at 20 degrees centigrade has a volume of 12 liters and a pressure of 15 atmospheres. Its temperature is raised to 3

LiRa [457]

P 15 atm

V₁ = 12x103 m3 -3 3 V₁ = 12x10 m" T₁ = 25°c T= 28815 K

P₁ = 1.52x10 Pa

Now, Finel quantities, T₂ = 35°C = 308.15 °K

V2= 851 = -3 3

Now

by ideal gas equation

P2Y2 T2

= PV, T2

1152 X106 x 12x16 3 x 308115 8,5×103 x 288,15 = Pa

=

21294×10 Pa

P₂ = 21264 Atm

final

pressure will be

21264 Adm.

Please check the attached file for a brief answer.

Learn more about the temperature at

brainly.com/question/24746268

#SPJ4

3 0

2 years ago

GIVING 17 POINTS PLS HELP ME!!!!

Novosadov [1.4K]

Hydropower can affect fish and other marine life which is the true statement and is denoted as option C.

<h3>What is Hydropower?</h3>

This is the process in which water energy is converted into electrical energy through the use of dams and turbines.

When the dams are created, it blocks the path of marine activities and limits them to certain activities such as reproduction.

Read more about Hydropower here brainly.com/question/8934285

#SPJ1

8 0

2 years ago