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kaheart [24]
3 years ago
11

Mrs. conley asks her class what kind of party they want to have to celebrate their excellent behavior. out of all the students i

n the class, 5 want an ice cream party. 7 want a movie party , 10 want a costume party the rest haven't decided. if 20% want an ice cream party how many students are in the class?
Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0
20% X Students = 5
20%/ 20% X Students=5/20%
Students = 25

Check
20% X 25 = 5
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Determine the common factors and HCF for each of the following terms.
Ahat [919]

Answer: Please see explanation column for answers

Step-by-step explanation:

When a number  divides into another number without a remainder, it s called a factor of that number.  Lets say we want to  find the common factors of two numbers, we get the  factors of each one and  compare them. The common factor is the one that is found in both lists

While The Highest common factor, is the highest factor number found in both lists.

b) 2b , 3b

Factors of 2b= 1, 2 and b

Factors of 3b=1, 3 and b

Common factors =1 and  b

HCF=1b

e) 5bc, 2c2, 3cd

Factors of 5bc=  1, 5, b, c

Factors of 2c2= 1,  2, c, c2

Factors of  3cd= 1, 3, c, d

Common factors = 1 and c

HCF= 1c

f) 4a2b, 8b2c, 6bcd

Factors of 4a2b=  1, 2, 4, a, a2, b

Factors of 8b2c= 1, 2, 4, 8, b, b2, c

Factors of  6bcd= 1, 2,3,6, b, c,d

Common factors = 1, 2 , b

HCF=  2b

3 0
3 years ago
12. x + y = 4
34kurt

Answer:

x =  -  \frac{2}{3}  \:  \:  \: y =  \frac{14}{3}

Step-by-step explanation:

Since we know -7x=y we use the substitution method and plug it in the top equation.

x + - 7x = 4

- 6x = 4

x =  -  \frac{4}{6}

or x=-2/3

Then plug it back in the the bottom equation

- 7( \frac { - 2}{3} ) = y

y=14/3

3 0
3 years ago
a bottle filled with weighs 42 pounds If the water by itself weighs 11 times as much as the bottle, what is the weight of the bo
natita [175]

Answer:

462 pounds

Step-by-step explanation:

weighs 42 pounds

    and the water 11 times more

 so, 42*11 = 462 pounds

4 0
4 years ago
"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"
erastovalidia [21]

Answer:

The exam can be answered with exactly 8 answers correct in 6435 ways.

Step-by-step explanation:

The order is not important.

For example, answering correctly the questions 1,2,3,4,5,6,7,8 is the same outcome as answering 2,1,3,4,5,6,7,8. So we use the combinations formula to solve this problem.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

"There are 15 questions on an exam. In how many ways can the exam be answered with exactly 8 answers correct?"

Combinations of 8 questions from a set of 15. So

C_{15,8} = \frac{15!}{8!(15-8)!} = 6435

The exam can be answered with exactly 8 answers correct in 6435 ways.

5 0
3 years ago
What is 30% of 70?<br> O 10<br> O 14<br> O 18<br> O 21<br> O 28
Sedaia [141]

Answer:

your answer is 21

Step-by-step explanation:

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7 0
2 years ago
Read 2 more answers
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