Subtract (5x^2+3)-(2x^2+4x-12)

Mathematics

2 answers:

irina1246 [14]2 years ago

7 0

Answer:

Final answer is $3x^2-4x+15$

Step-by-step explanation:

we have been given an expression $(5x^2+3)-(2x^2+4x-12)$ .

Now we need to subtract them.

We can subtract like terms only that has same variable with same exponent.

$(5x^2+3)-(2x^2+4x-12)$

$=5x^2+3-2x^2-4x+12$

$=5x^2-2x^2-4x+3+12$

$=(5-2)x^2-4x+(3+12)$

$=(3)x^2-4x+(15)$

$=3x^2-4x+15$

Hence final answer is $3x^2-4x+15$

Fynjy0 [20]2 years ago

7 0

Answer:

(5x^2+3)-(2x^2+4x-12) = 3x²-4x+15.

Step-by-step explanation:

We have given the expression:

(5x²+3)-(2x²+4x-12)

We have to subtract.

(5x²+3)-(2x²+4x-12)

5x²+3-2x²-4x+12

5x²-2x²-4x+3+12

3x²-4x+15

3x²-4x+15 is the answer.

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A firm’s marketing manager believes that total sales for next year will follow the normal distribution, with a mean of $3.2 mill

klasskru [66]

Answer:

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Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

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$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

In millions of dollars,

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