Answer:
∠a = 10°
Step-by-step explanation:
The measure of ∠a = x
The measure of ∠b = 4x-30
It is also mentioned that the measure a and measure b are vertical angles. We need to find the value of a.
For vertically opposite angles,
∠a = ∠b
x = 4x-30
or
4x-30=x
Taking like terms together,
4x-x= 30
3x = 30
x = 10
So, the meausre of ∠a is equal to 10°.
Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle
Answer:
86400 ways
Step-by-step explanation:
Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.
Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.
After picking the places for the women, we will now fill each gap between two women with a man.
We have 6 men. Thus, number of ways to arrange the men is 6!
Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways
Answer:
S=49
Step-by-step explanation:
Any triangle has an interior angle of 180.
So just add them up and set the sum equal to 180 degrees.
2s+s+33=180
3s=180-33
3s=147 . Divide both sides by 3 to isolate variable s
s=49
Answer:


Step-by-step explanation:
Given

Required
Determine: 
First, we calculate f(x + h)



So, we have:





