Answer:
22.5 UK£
Step-by-step explanation:
i just searched it up on google.
Answer: A
Step-by-step explanation:
X values to the right of the y axis are positive. X values to the left of the y axis are negative.
Y values above the x axis are positive.
Y values below the x axis are negative.
Pairs of coordinates are always noted as (x,y) with the x value of a point given first and the y value of that same point given second.
Answer:
√x
Step-by-step explanation:
Step 1: First, simplify -3⁄6 to -½.
Step 2: According to the Negative Exponential Rule, you bring the denominator to the numerator while ALTERING THE INTEGER SYMBOL FROM NEGATIVE TO POSITIVE:
bⁿ = 1\b⁻ⁿ
1\x-¹\² = x¹\²
Step 3: Again, using the Definition of Rational Exponents, rewrite this rational exponent as a radical:
x¹\² = √x
I am joyous to assist you anytime.
Answer:
more information is needed
Step-by-step explanation:
inadequate info :(
Answer:
The power of the test is 0.67.
Step-by-step explanation:
The complete question is:
A researcher is evaluating the influence of a treatment using a sample selected from a normally distributed population with a mean of μ = 80 and a standard deviation σ = 20. The researcher expects a 12-point treatment effect and plans to use a two-tailed hypothesis test with α = 0.05. Compute the power of the test if the researcher uses a sample of n = 16 individuals
.
Solution:
The information provided are:

The expected mean is:

The critical <em>z</em>-score at <em>α</em> = 0.05 for a two-tailed test is:
<em>z</em> = 1.96
*Use a <em>z-</em>table.
Compute the test statistic value as follows:

The power of statistical test is well-defined as the probability that we reject a false null hypothesis.
Power = Area to the right of the critical <em>z</em> under the assumption that H₀ is false.
Location of critical <em>z</em> (in H₀ is false distribution) = 
This is negative because the critical z score is to the left of the mean of the H₀ in false distribution.
Area above z = -0
.44.
Compute the value of P (Z > -0.44) as follows:

Thus, the power of the test is 0.67.