What is 10c-3(5c-1)=2(4c+3)-5c

Which expression could be used to determine the area of the square? A square has side lengths of 10.75 meters. (2)(10.75) (4)(10

kolezko [41]

Answer:

Step-by-step explanation:

area of square=10.75² m²

or A=(10.75)(10.75) m²

3 0

3 years ago

Use a normal approximation to find the probability of the indicated number of voters. In this case assume that 150 eligible vote

alexdok [17]

The number of people who voted follows a binomial distribution with probability of having voted $p=0.22$ and $n=150$ subjects, which means the approximating normal distribution should have mean $np=33$ and standard deviation $\sqrt{np(1-p)}\approx5.07$ .

With the continuity correction, you have

$\mathbb P(X$

8 0

3 years ago

57 is 13.5% of what number?

kondaur [170]

Let, the number = x
It would be: x * 0.135 = 57
x = 57 / 0.135
x = 422.23

Hope this helps!

6 0

3 years ago

25 to 75 in ratio lowest term

ANTONII [103]

25 to 75 in lowest terms:

25:75 = 1:3

8 0

3 years ago

Angela and Jayden were at track practice. The track is 2/5 kilometers around. Angela ran 1 lap in 2 Minutes. Jayden ran 3 laps i

I am Lyosha [343]

Answer:

Step-by-step explanation:

Angel ran 1 lap in 2 minutes.

Jayden ran 3 laps in 5 minutes.

How many minutes does it take Angel to run one kilometer? What about Jayden?

How far does Angel run in one minute? What about Jayden?

Who is running faster? Explain your reasoning.

IM Commentary

Parts (a) and (b) of the task ask students to find the unit rates that one can compute in this context. Part (b) does not specify whether the units should be laps or km, so answers can be expressed using either one.

The purpose of part (c) is to give students an opportunity to make use of the unit rates that they found in parts (a) and (b). While it is possible for students to solve part (c) in other ways, the solution shown represents the kind of reasoning with unit rates that 7th graders should be able to do. It is important to note that the answer can be determined using different unit rates as long as the reasoning behind it is correct.

Solution

We can create a table that shows how far each person runs for a certain number of laps:

Number of laps Number of km

1 25

2 45

3 65

We can see from the table that 1 km is exactly half way between 2 and 3 laps. So it will take 2.5 laps to run 1 km.

Since it takes Angel 2 minutes to run 1 lap, she will take

2.5 laps1 km⋅2 minutes1 lap=5 minutes1 km.

So it takes Angel 5 minutes to run 1 km.

Since it takes Jayden 5 minutes to runs 3 laps, she runs 1 lap in 53 minutes. Thus, it takes Jayden

2.5 laps1 km⋅5 minutes3 laps=52⋅53 minutes/km=256 minutes/km=416 minutes/km.

So it takes Jayden 416 minutes to run 1 km.

Angel runs 1 lap in 2 minutes so she runs 12 lap in 1 minute. Since 1 lap is 25 km, 12 lap is 15 km. So she also runs 15 km in one minute.

Since Jayden runs 1 lap in 53 minutes, she will run 35 laps in 1 minute. Since Jayden runs 1 km in 256 minutes, she will run 625 km in 1 minute.

Jayden runs the same distance in less time than Angel (alternatively, Jayden runs farther in the same time than Angel), so Jayden is running faster than Angel.

4 0

2 years ago