Answer:
b. pass through pores in the capillary endothelium
Explanation:
The fenestrated capillaries and sinusoids have pores in their endothelium. These pores or the intracellular clefts vary in size between the fenestrated capillaries and sinusoids. Sinusoids have larger intracellular clefts. The pores serve as a passage for the movement of water-soluble substances, proteins and other substances that cannot cross the hydrophobic interior of the cell membranes.
Water-soluble hormones also cannot pass through the capillary walls. Therefore, these hormones pass through the pore or the fenestrations present in the endothelium of capillaries.
its either The division cycle of most eukaryotic cells is divided into four discrete phases: M, G1, S, and G2. M phase (mitosis) is usually followed by cytokinesis. S phase is the period during which DNA replication occurs or In eukaryotes, the cell cycle consists of four discrete phases: G1, S, G2, and M. The S or synthesis phase is when DNA replication occurs, and the M or mitosis phase is when the cell actually divides. The other two phases — G1 and G2, the so-called gap phases — are less dramatic but equally important. hope this helped!!
Answer: Hey again!
Option (a) is the correct answer.
Explanation:
Elemental form of carbon means the pure form of carbon, that is, carbon is present in its natural form.
An elemental form also means that the pure atoms are not attached to any other atom.
For example, diamond is an allotrope of carbon in which there are only carbon atoms attached to each other and no other atom is present in it.
Whereas methane has carbon and hydrogen atoms attached to each other therefore, it is not an elemental carbon. And proteins include different atoms attached to each other.
Thus, we can conclude that diamond is an example of elemental carbon.
Explanation:
Correct question:
if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction)?
Answer:
100%
Explanation:
Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".
There is no choice? But if I was thinking it would be idk
