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Dimas [21]
3 years ago
8

a turtle and a snail are 360 meters apart, and they start to move toward each other at 3 pm. if the turtle is 11 times as fast a

s the snail, and they meet at 3:40 p.m, find the speed of each.
Mathematics
2 answers:
Nadusha1986 [10]3 years ago
8 0
Speed= distance/ time
speed = 360 / 40 = 90
abruzzese [7]3 years ago
4 0

Let u be speed of snail and x be distance traveled by snail.

We have been given that turtle is 11 times as fast as snail. So speed of turtle will be 11\cdot u. We are also given that they traveled a distance of 360 kilometers. So distance traveled by turtle will be 360-x.

Furthermore, we are given that they took 40 minutes to complete total distance.

Since we know \text{Speed}=\frac{\text{Distance}}{Time}

After substituting our given information into this formula we will get two equation and two unknowns.

u=\frac{x\text{ metres}}{40\cdot 60\text{ seconds}}

11\cdot u=\frac{(360-x)\text{ metres}}{40\cdot 60\text{ seconds}}\\

Now substituting u's values in second equation we will get

11\cdot \frac{x\text{ metres}}{240\text{ seconds}}=\frac{(360-x)\text{ metres}}{240\text{ seconds}}\\

11\cdot x =360-x\\
12\cdot x=360\\
x=30\text{ metres}

Now we will find speed of snail (u),

u=\frac{30\text{ metres}}{240\text{ seconds}}\\
u=\frac{1\text{ metres}}{8\text{ seconds}}

Now let us find speed of turtle (11u),

11\cdot u=11\cdot \frac{1\text{ metres}}{8\text{ seconds}}\\
\\
=\frac{11\cdot \text{ metres}}{8\text{ seconds}}

Therefore, speed of snail is 1/8 meters per second and speed of turtle is 11/8 meters per second.


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