2x-4y=-16
ax+4y=6 +
--------------------
2x+ax=-10; for x=-2,
2(-2)+a(-2)=-10
-2a=-10+4
a=-6/-2
a=3
<span>C. (4,3)
Draw and plot on a graph and (4,3) could be the other end point, which
x < 5
y > 2</span>
The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay
dollar each day</u>.
So, the total amount needed to pay for 5 days
dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....

So, the original price for one lunch special is $19.
Answer:
294 cars.
Step-by-step explanation:
Let x be the number of cars and y be the number of trucks.
We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.
Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

We can see that total number of cars sold on two dealerships will be
.
We will use substitution method to solve for x. From equation (1) we will get,

Substituting this value in equation (2) we will get,

Now let us have a common denominator.


Upon multiplying both sides of our equation by 2 we will get,





Therefore, the total number of cars sold by two dealerships is 294.
Answer:
12.53 miles
Step-by-step explanation:
6² + 11² = x²
36 + 121 = x²
157 = x²
x = 12.53 miles