Given:
∠JEK + ∠DFH = 90°
Find:
relationship, if any, of ∠JEK to angles CFL, HFG, LFE
Solution:
We note that ∠DFG = 90° = ∠DFH + ∠HFG, so ∠JEK ≅∠HFG.
We also note that ∠HFG and ∠CFL are vertical angles, so ∠JEK ≅∠CFL.
And ∠LFE and ∠DFH are vertical angles, so ∠JEK + ∠LFE = 90°.
Evaluating the choices, we find
A) false. The angles are not complementary, they are equal.
B) false. The angles are not equal, they are complementary.
C) false. The angles are not supplementary, they are equal.
D) TRUE. The angles are equal.
The appropriate choice is ...
D) ∠JEK ≅∠CFL
Answer:
The constant in the polynomial is 9. A constant number is a number that does not change during the equation. This equation is 4x² + 9. Since you are just adding 9 the number of 9 does not change. If you were multiplying 9 it would not be a constant anymore because it does not stay the same throughout the equation.
Hope This Helps :)
Answer:
Step-by-step explanation:
y - 5 = -8(x - 1)
y - 5 = -8x + 8
y = -8x + 13
Answer:
k=20.
Explanation: First we find where f(x) has its local extrema: f'(x)=3x2−10x+3. The critical points are roots of the equation: 3x2−10x+3=0.
Answer: 254,34 mm².
Step-by-step explanation:
