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joja [24]
3 years ago
9

X² - 5x + 6 = 0 (R: 2, 3)

Mathematics
1 answer:
Firlakuza [10]3 years ago
4 0
I'm sending you two screenshots of the explanation I hope this helps.

You might be interested in
What is -13/6 as a repeating decimal​
monitta

Answer:

-2.16 repeating

Step-by-step explanation:

Convert the fraction to a decimal by dividing the numerator by the denominator.

6 0
3 years ago
An object dropped from a height of 600 feet has a height, h(t), in feet after t seconds have elapsed, such that h(t)=600 - 16t^2
gulaghasi [49]

Answer:

t as a function of height h is  t = √600 - h/16

The time to reach a height of 50 feet is 5.86 minutes

Step-by-step explanation:

Function for height is h(t) = 600 - 16t²

where t = time lapsed in seconds after an object is dropped from height of 600 feet

t  as a function of height h

replacing the function with variable h

h = 600 - 16t²

Solving for t

Subtracting 600 from both side

h - 600 = -16t²

Divide through by -16

600 - h/ 16 = t²

Take square root of both sides

√600 - h/16 = t

Therefore, t = √600 - h/16

Time to reach height 50 feet

t = √600 - h/16

substituting h = 50 in the equation

t = √600 - 50/16

t = √550/16

t= 34.375

t = 5.86 minutes

7 0
4 years ago
Find the Distance between points A and B: A (8, 12) B: (2, 4)
mote1985 [20]
ANSWER-the distance is (6,8)
if you set the equation up from 2-8=6 which is your x value and 4-12=8 is your y value it should also give you your Distance between the two points
4 0
3 years ago
Find MN to the nearest tenth?<br><br> A. 11.34<br> B. 16.1<br> C. 39.6<br> D. 23.8
Nana76 [90]

As the question say this problem is a practice of the law of cosines!

The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c

The law can also be written as c=sqrt(a^2+b^2-2abcosc)

Now use this formula!(note cos 100 degrees is about 0.8623)

c=sqrt(15^2+16^2-2*15*16*cos100)

solving this we can MN is about 23.75

Round this to the nearest tenths now!

We get 23.8!

Thus the answer is D

5 0
3 years ago
A right cylinder has a radius of r inches and height of 2r inches.
lys-0071 [83]

Answer:

Part a) The lateral area is 4r^{2} \pi \ in^{2}

Part b) The area of the two bases together is 2r^{2} \pi\ in^{2}

Part c) The surface area is 6r^{2} \pi\ in^{2}

Step-by-step explanation:

we know that

The surface area of a right cylinder is equal to

SA=LA+2B

where

LA is the lateral area

B is the area of the base of cylinder

we have

r=r\ in

h=2r\ in

Part a) Find the lateral area

The lateral area is equal to

LA=2\pi rh

substitute the values

LA=2\pi r(2r)

LA=4r^{2} \pi\ in^{2}

Part b) Find the area of the two bases together

The area of the  base B is equal to

B=r^{2} \pi\ in^{2}

so

the area of the two bases together is

2B=2r^{2} \pi\ in^{2}

Part c) Find the surface area of the cylinder

SA=LA+2B

we have

LA=4r^{2} \pi\ in^{2}

2B=2r^{2} \pi\ in^{2}

substitute

SA=4r^{2} \pi+2r^{2} \pi=6r^{2} \pi\ in^{2}

4 0
3 years ago
Read 2 more answers
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