Question

Calculate 2B%20%5Cfrac%7B8%7D%7B12%7D%20%20%20" id="TexFormula1" title=" \frac{24}{6}+ \frac{4}{3}+ \frac{12}{2}+ \frac{8}{12} " alt=" \frac{24}{6}+ \frac{4}{3}+ \frac{12}{2}+ \frac{8}{12} " align="absmiddle" class="latex-formula">

Answer 1

$\boxed{\displaystyle{ \frac{24^{(2}}{6} +\frac{4^{(4}}{3} + \frac{12^{(6}}{2} + \frac{8}{12} = }} \\ \\ \boxed{\displaystyle{ \frac{48}{12}+ \frac{16}{12}+ \frac{72}{12}+ \frac{8}{12}= \frac{168}{12}=\ }} \\ \\ \\\\\huge\text{The answer is 168/12 !}$