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Which ratio forms a proportion with 18/27

JulsSmile [24]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

The given ratio is $\frac{18}{27}$

9 is the common factor of 18 and 27

divide numerator and denominator by 9

$\frac{18/9}{27/9} =\frac{2}{3}$

hence $\frac{2}{3}$ is proportion with $\frac{18}{27}$

6 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

Supposing 60 out of 100 scores are passing scores, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago

Kylie is ordering 9 pizzas for her party. Each pizza is either thin crust or deep dish. Each thin crust pizza costs $20, and eac

nirvana33 [79]

Answer:

the answer is A. 2 thin crust pizzas

8 0

2 years ago

Read 2 more answers

Equivalent to (6 + y) × 5?

Sergeeva-Olga [200]

The answer is:
It’s equivalent to 30+5y

6 0

3 years ago

Read 2 more answers

A bag has 3 red marbles, 2 blue, 4 greens and 1 yellow. What is the probability of pulling a blue, putting it back

Tomtit [17]

Answer: 2/25

Step-by-step explanation: Since we are replacing the marbles, these two events are independent which means that the outcome of the first does not affect the outcome of the second.

First find the probability of selecting a blue marble.

There are 2 favorable outcomes, the blue marbles,

and 10 possible outcomes, all the marbles in the bag.

So the probability of selecting a blue marble is 2/10 or 1/5.

Always reduce when finding probability

Now we find the probability of selecting a green marble.

There are 4 green marbles and 10 total so the probability of

selecting a green marble is 4/10 or 2/5.

Now we multiply the probabilities.

So we have 1/5 x 2/5 or 2/25.

3 0

3 years ago