Question

F(x)=9(x-8) find f^-1(x)

Answer 1

Answer:

$f^{-1}$(x) = $\frac{1}{9}$ x + 8

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 9(x - 8) ← divide both sides by 9

$\frac{y}{9}$ = x - 8 ( add 8 to both sides )

$\frac{y}{9}$ + 8 = x

Change y back into terms of x with x = $f^{-1}$(x) , thus

$f^{-1}$(x) = $\frac{1}{9}$ x + 8