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Hunter-Best [27]
4 years ago
13

guy wire attached to a telephone pole makes a 67-degree angle with the ground. at a point 20ft farther out from the guy wire the

angle of elevation of the top of the pole is 35 degree. how long is the guy wire
Mathematics
2 answers:
Lynna [10]4 years ago
7 0

Answer:

It is best to draw the situation given above to understand the problem better. You will see that there are two right triangles that can be made. One would have the angle 67 degrees and the other with angle 35 degrees. We calculation as follows:

From the triangles, we can set up two equations with two unknowns:

tan 67 = h/x

tan 35 = h/(20+x)

h = 19.93 ft

Step-by-step explanation:

qaws [65]4 years ago
4 0
It is best to draw the situation given above to understand the problem better. You will see that there are two right triangles that can be made. One would have the angle 67 degrees and the other with angle 35 degrees. We calculation as follows:

From the triangles, we can set up two equations with two unknowns:
tan 67 = h/x
tan 35 = h/(20+x)

h = 19.93 ft
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What is the scientific notation of 42
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If x =√63 and y = √24, what is the approximate value of x + y2?
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4 0
3 years ago
A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

80P+40Q=48800

Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

\displaystyle R=Q\cdot \frac{1120-Q}{2}

\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

R=\$156,800

And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
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