The number 6√3 is between what two integers and is closer to which integer on the number line.

If a point is in the fourth quadrant, then its coordinates are negative

Two lines are perpendicular if and only if the two lines intersect at right angles. If a point is in fourth quadrant,then it coordinates at negative. If thecoordinates are negative, then thepoint is in the fourth quadrant. If a figure is a triangle, then it has three sides.

3 0

3 years ago

Which number produces

Dvinal [7]

Answer:

A is the answer.

Step-by-step explanation:

A fraction plus a fraction is equal to a fraction. An irrational number cannot be expressed as a fraction.

0.3333333 even though it looks like an irrational number it is actually: 1/3

3/5 is already a fraction so adding it with another fraction will NOT equal an irrational number (decimal)

-0.75 is equal to -3/4 (75/100 => 3/4). Same thing that applies above.

However, Pi cannot be expressed as a fraction exactly. You can round up like 3.14. However it is not the full number. So 3.141592654....+(3/4) is not going to add up perfectly into a fraction.

In short, a fraction is a rational number. Rational + Rational = Rational. Irrational + Rational = Irrational.

3 0

3 years ago

Read 2 more answers

Which expressions are equivalent to 1.5?

3241004551 [841]

Answer:

B and C

Step-by-step explanation:

We can just solve each to find which expressions are equal to 1.5.

A) 0.15 × 100 = 15

B) 15.0 ÷ 10 = 1.5

C) 0.15 × 10 = 1.5

D) 0.15 ÷ 10 = 0.015

E) 1.5 ÷ 100 = 0.015

From our results, we see that B and C are the only answers that equal 1.5.

6 0

3 years ago

A wall with a height of 20 feet is braced with a support post that forms a 30 degree angle with the top of the wall. What is the

dexar [7]

The length of the support post is 40 ft.

Solution:

Given, the height of the wall is 20 ft; support post forms 30 degree

Refer the attached image

Let us name the triangle as ABC where AB is the wall (opposite side) of 20 ft and $\angle A$ is 30 degree ( $\theta$ ) and AC is the length of the post.

To find: The length of the post (AC)

we know the formula, $sin\theta=\frac{opp}{hyp}$ (trigonometric formula)

On substituting the values we get,

$\Rightarrow sin(30^{\circ})=\frac{20}{AC}$

The value of sin 30 degree is 0.5

$\Rightarrow 0.5=\frac{20}{AC}\rightarrow AC=\frac{20}{0.5}\rightarrow AC=40 ft$

3 0

3 years ago

Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region

yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

s = side

Area of Triangle = bh/2

b = base
h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

Step One: Find the length of PT

Given:

PR = 4 cm
RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago