The equation would be
y = x + 3
Answer:
4
Step-by-step explanation:
Func 2 is -2
Func 3 is 1
Func 4 is 8
Func 1 is unknown
Answer:
e^ (5 ln (x + 1)) = (x + 1)^5
Step-by-step explanation:
e5 In (x + 1) or did you mean e^ (5 ln (x + 1))
because then this would simplify a lot
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5)
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
or did you mean (e^5) ( ln (x + 1)) = ln [(x+1)^(e^5)]
But I think you meant:
e^ (5 ln (x + 1)) = e ^ (ln (x + 1)^5) = (x + 1)^5
3x-4y=10
or,4y=3x-10
or,y=(3x-10)/4
so,y=3/4 x-5/2
0.
It is impossible for 151 to be selected, as it is outside the range of numbers (1 to 100) that can be selected. Therefore the probability is 0.
