How many 3 letter permutations are possible for the letters s t u d y h a r d
1 answer:
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Answer:
x = 3; y = 6; z =4
Step-by-step explanation:
The point J is the circumcentre of the triangle.
It is equidistant from the vertices. So
2x + 2 = 8
2x = 6
x = 3
2y - 4 = 8
2y = 12
y = 6
If FI = 9, HI = 9. Then,
3z - 3 = 9
3z = 12
z = 4
So, x = 3; y = 6; z =4.
