Question

F(x)=x^3-9x What is the average rate of change of f over the interval (1,6]?

Answer 1

Answer:

34

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 1, 6 ]

f(b) = f(6) = 6³ - 9(6) = 216 - 54 = 162

f(a) = f(1) = 1³ - 9(1) = 1 - 9 = - 8, thus

average rate of change = $\frac{162-(-8)}{6-1}$ = $\frac{170}{5}$ = 34