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Airida [17]
3 years ago
7

I need major help on these set theory questions!!!

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

4. option D

5. option C

6. option A

7. option A

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F(t)=2t-3<br><br><br> f(7)=<br><br> Pleasssssssse helllllpppp<br> I only have 2 minutes 15 points
yaroslaw [1]
F(7)= 11 if this is right mark 5 star

6 0
3 years ago
Read 2 more answers
1-5. Evaluate each absolute value expression. Can you help me with this and if you can explain it to me thanks you
mihalych1998 [28]

Well when it comes to absolute value remember that whatever number is inside the two straight lines will always come out as a positive.

a) [54] would still be 54

b)-[-7 3/5] so first you get the absolute value which comes out to 7 3/5 but because there is a negative sign out side of the two parallel lines, the answer would be -7 3/5

c)[3]-[-1] the absolute value of 3 is 3 and the absolute value of -1 is 1. So the expression would be 3-1 which comes out to 2

d)[2.2-5.13] 2.2-5.13 would equal -2.93 but since it is in the absolute value, the answer would come out as 2.93

Hope this helps!

3 0
3 years ago
Quadrilateral RSTU has vertices R(-6, -3), S(3, 3), and T(4, -1). What are the coordinates of vertex U if
Natasha_Volkova [10]

9514 1404 393

Answer:

  c)  (-5, -7)

Step-by-step explanation:

In a parallelogram, the midpoints of the diagonals are the same point. This means ...

  (R+T)/2 = (S+U)/2

  R +T -S = U

  (-6 +4 -3, -3 -1 -3) = U = (-5, -7)

7 0
3 years ago
Please explain number 10 in a step by step process.
Aleonysh [2.5K]

Good evening ,

______________

Answer:

a=3

___________________

Step-by-step explanation:

Look at the photo below for the answer.

:)

3 0
3 years ago
Read 2 more answers
Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
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