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Travka [436]
3 years ago
15

John's age increased by 11 is 5 less than 5 times his age. How old is he? If x represents John's age, which of the following equ

ations could be used to solve this problem?
Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0
X + 11 = 5x -5
x-x+11=5x-x-5
11 = 4x -5
11+5 = 4x -5+5
16 = 4x
16/4 = 4x/4
x = 4


Arturiano [62]3 years ago
7 0
Not entirely sure about the equation, but hes 4. 4 plus 11 is 15, fifteen plus 5 is 20. (fifteen is five less than 20) and 20 is 5 times his age, which is 4
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Answer:

17 years

Step-by-step explanation:

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3 years ago
Rewrite the given inequality as two linear inequalities. ∣8x+9∣<4
Nostrana [21]

Answer:

8x+9 and 8x+9>-4.

Step-by-step explanation:

The given inequality is

|8x+9|

We need to rewrite the given inequality as two linear inequalities.

We know that |8x+9|>0 but (8x+9) can be positive or negative.

For |8x+9|,  the value of (8x+9) must be lies between -4 and 4.

i.e., -4

If 8x+9 positive, then

8x+9      ...(1)

If 8x+9 negative, then

8x+9>-4      ...(2)

Therefore, the two inequalities are 8x+9 and 8x+9>-4.

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3 years ago
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Yes they are similar because similar means same shape but different scale


Step-by-step explanation:

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8 0
3 years ago
Para la actuacion del dia de la madre , se colocaron en el patio 40 filas de 32 asientos para cada una. Para la siguiente actuac
Margarita [4]

Answer:

En 64 filas habrá 51 asientos

en 60 filas habrá 48 asientos

Step-by-step explanation:

Spanish

Primero se averigua la relación entre las filas y los asientos.

40: 32

Dividiendo por 8

5: 4

Usando esta relación podemos encontrar el número de asientos en el número dado de filas.

Si el número de filas es 64 entonces

Asientos de filas

64 x

5 4

Uso de la regla de productos cruzados

x = 64 * 4/5 = 51,2

En 64 filas habrá 51 asientos

Si el número de filas es 60 entonces

Asientos de filas

60 x

5 4

Uso de la regla de productos cruzados

x = 60 * 4/5 = 48

en 60 filas habrá 48 asientos

English

First the ratio of the rows to the seats is found out

40 : 32

Dividing by 8

5: 4

Using this ratio we can find the number of seats in the given number of rows.

If the number of rows is 64 then

Rows           seats

64                 x

5                   4

Using cross product rule

x= 64*4/5= 51.2

In 64 rows there will be 51 seats

If the number of rows is 60 then

Rows           seats

60                 x

5                   4

Using cross product rule

x= 60*4/5= 48

in 60 rows there will be 48 seats

4 0
3 years ago
Can anyone solve this this problem in order please
Svetllana [295]

Instead of using letters from A to AA, let's use numbers. Also, let's number the rows from 0 to 26. So, our labelling will go like this:

\begin{tabular}{c|c}\text{\textbf{Row}}&\text{\textbf{Index}}\\A&0\\B&1\\C&2\\D&3\\\vdots&\vdots\\AA & 26\end{tabular}

The reason for this labelling is the following: we know that row A has 9 seats, and the following rows have three more seats than the previous one. Let's build a table like the previous one, containing the number of seats for the first few rows:

\begin{tabular}{c|c}\text{\textbf{Index}}&\text{\textbf{\# of seats}}\\0&9\\1&12\\2&15\\3&18\\4 & 21\\\vdots&\vdots\end{tabular}

So, as you can see, the i-th row has exactly 3i more seats than the first one.

So, we have the following sequence:

a_0=9,\ a_1=12,\ a_2=15,\ldots,\ a_n = 3n+9

Which defines the number of seats for each row.

Answering the questions is now easy: the 27 row, AA, is the 26th term in our sequence:

a_{26} = 3\cdot 26+9 = 78+9 = 87

The total number of seats is the sum of all the terms in the sequence:

\displaystyle \sum_{i=0}^{26}3n+9 = \sum_{i=0}^{26}3n + \sum_{i=0}^{26}9 = 3\sum_{i=0}^{26}n + 27\cdot 9 = 3\dfrac{26\cdot 27}{2} + 243 = 3\cdot 13 \cdot 27 + 243 = 1053 + 243 = 1296

Finally, let a be the number of adult tickets, and s be the number of student tickets. We know that twice as many student tickets were sold as adult tickets, so we have

s = 2a

Since the show was a sold out, we have

a+s = 1296 \iff a+2a = 1296 \iff 3a = 1296 \iff a = 432

So, 432 adult tickets were sold, which implies that

s = 432\cdot 2 = 864

student tickets were sold. Let c be the cost of a student ticket. Adult tickets then cost 3c, and the total revenue is

432\cdot 3c + 864c = 1296c+864c = 2160c

So, we have

2160c =6480 \iff c = \dfrac{6480}{2160} = 3

8 0
3 years ago
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