No pair of lines can be proven to be parallel considering the information given, therefore, the answer is: D. None of the options are correct.
<h3>When are Two Lines Proven to be Parallel to each other?</h3>
Two lines that are cut across by a transversal can be proven to be parallel to each other if:
- The alternate interior angles along the transversal and on the two lines are congruent [alternate interior angles theorem].
- The alternate exterior angles along the transversal and on the two lines are congruent [alternate exterior angles theorem].
- The same-side interior angles along the transversal and on the two lines are supplementary [same-side interior angles theorem].
- The corresponding angles along the transversal and on the two lines are congruent [corresponding angles theorem].
Thus, given the following information:
m∠2 = 115°
m∠15 = 115°
With only these two angles given, we can't use any of the theorems to prove that any of the two lines are parallel because angle 2 and angle 15 are located entirely on two different transversals that crosses two lines.
In summary, we can conclude that:
D. None of the options are correct.
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Answer:
0
Step-by-step explanation:
3x^2 + y ( If x = 1, and y = -3)
= 3(1)^2 + (-3)
= 3 + -3
= 0
Cheers.
Answer:
x equals 13
10 + x = 23
x=23-10
Step-by-step explanation:
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stay salty,
be positive...
Answer:
-3/2
Step-by-step explanation:
We can find the slope between two points using
m = (y2-y1)/(x2-x1)
= (-7 - -1)/(5 - 1)
(-7+1(/(5-1)
-6/4
-3/2