All categories

2 years ago

A person with a phobia of horses would likely benefit most from which type of therapy?

Advanced Placement (AP)

2 answers:

Vaselesa [24]2 years ago

8 0

D a family theraphy is the answer.

ValentinkaMS [17]2 years ago

8 0

The correct answer with all due reapect to previous peeson is A.
Here is why:
"Systematic desensitization is a behavioral technique commonly used to treat fear, anxiety disorders and phobias. Using this method, the person is engaged in some type of relaxation exercise and gradually exposed to an anxiety producing stimulus, like an object or place.

You might be interested in

Which of the following statements describes the effect of the rhetorical questions in the third paragraph? I. The questions elic

Kay [80]

Answer:

I think it's D. I and II only but I'm not sure...

Explanation:

8 0

3 years ago

Read 2 more answers

All______nervous system is responsible for our fight-or-flight response

skad [1K]

adrenal glands are used for the fight and flight responses.

6 0

3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

2 years ago

Max Points, and Brainliest!

Gemiola [76]

Answer: what the heck of questions is this

Explanation:

7 0

3 years ago

When a star burns its fuel at a faster rate, late in its life, the extra energy flow causes what to happen?

Scilla [17]

Answer:

The outer layer of the star expands

Explanation:

Late in life, when the hydrogen fuel for nuclear fusion is exhausted, the core of the star tends to collapse. That process generates heat that pushes the outer layers of the star outward.

The outer layer of the star expands.

4 0

3 years ago