Todd is saving for a vacation. The cost of his vacation is 1,089. Todd has a year to save the money. About how much does he need
2 answers:
Answer:
He needs to save $90.75 each month to reach his goal.
Step-by-step explanation:
We have the cost of his vacation that is $1089.
We know that Todd has a year to save the money.
We know that a year in terms of time is twelve months (12 months).
If we want to calculate how much does he need to save each month we need to divide the total cost of his vacation by the amount of months in a year ⇒
We find that Todd needs to save $90.75 per month to reach his goal.
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The probability that all three players obtain an odd sum is 3/14.
<h3>What is probability?</h3>The probability is the ratio of possible distributions to the total distributions.
I.e.,
Probability = (possible distributions)/(total distributions)
<h3>Calculation:</h3>Given that,
There are nine tiles - 1, 2, 3,...9, respectively.
A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.
In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.
The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.
So,
One player can be selected in ways.
The 3 odd tiles out of 5 can be selected in ways.
The remaining 2 odd tiles can be selected and distributed in ways.
The remaining 4 even tiles can be equally distributed in ways.
So, the possible distributions = ×
×
×
⇒ 3 × 10 × 2 × 6 = 360
To find the total distributions,
The first player needs 3 tiles from the 9 tiles in ways
The second player needs 3 tiles from the remaining 6 tiles in ways
The third player takes the remaining tiles in 1 way.
So, the total distributions = 84 × 20 × 1 = 1680
Therefore, the required probability = (possible distributions)/(total distributions)
⇒ Probability = 360/1680 = 3/14.
So, the required probability for the three players to obtain an odd sum is 3/14.
Learn more about the probability of distributions here:
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