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Makovka662 [10]
3 years ago
14

Todd is saving for a vacation. The cost of his vacation is 1,089. Todd has a year to save the money. About how much does he need

to save each month to reach his goal
Mathematics
2 answers:
Rashid [163]3 years ago
4 0
Todd needs to save $90.75 per month to reach his goal
sveticcg [70]3 years ago
4 0

Answer:

He needs to save $90.75 each month to reach his goal.

Step-by-step explanation:

We have the cost of his vacation that is $1089.

We know that Todd has a year to save the money.

We know that a year in terms of time is twelve months (12 months).

If we want to calculate how much does he need to save each month we need to divide the total cost of his vacation by the amount of months in a year ⇒

\frac{1089}{12}=90.75

We find that Todd needs to save $90.75 per month to reach his goal.

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The final amount of yards the team has is 8 yards.

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Jim borrows $790 for 4 months. He pays a simple interest rate of 6%. How much interest must he pay? Round your answer to the nea
nydimaria [60]

Answer:

Jim will be paid $150 or 30% to his account.

Step-by-step explanation:

Have a great day :)

3 0
3 years ago
What is 4,234 rounded to the nearest ten thousand?
nirvana33 [79]
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7 0
3 years ago
The sum of three numbers is 855. One of the numbers, x, is 50% more than the sum of the other two numbers. What is the value of
Snowcat [4.5K]

Answer:

The value of x = 513

Step-by-step explanation:

Let x, y, and z be the three numbers

Given

x+y+z=855

Assuming x be the number which is 50% more than the sum of the other two numbers.

i.e.

(150)% of (y+z) = 1.5(y+z)

                y + z = x/1.5

As we know that

x + y + z = 855

substituting y + z = x / 1.5 in the equation

x+\frac{x}{1.5}=855

Multiply both sides by 1.5

x\cdot \:1.5+\frac{x}{1.5}\cdot \:1.5=855\cdot \:1.5

1.5x+x=1282.5

2.5x=1282.5

Divide both sides by 2.5

\frac{2.5x}{2.5}=\frac{1282.5}{2.5}

x = 513

Therefore, the value of x = 513

8 0
3 years ago
Help for 3,4,5, and 6
Firdavs [7]

I think you forgot to put an image, attach a new one with the questions.

3 0
2 years ago
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