do parentheses first which gives you 42-4+111 then aubtract to get 38+111 which equals 149
Answer:
i think its C: none of the answers are correct
Answer:
Below in bold
Step-by-step explanation:
The sequence is:
3, x, y, 18
If this is an A P then
x - 3 = y - x
2x - y = 3 (A) and
y - x = 18 - y
2y - x = 18 (B)
Multiply (A) by 2:
4x - 2y = 6 (C)
Adding B and C:
3x = 24
x = 8.
and
2y - 8 = 18
2y = 26
y = 13.
So x = 8 and y = 13.
b) ar + ar^2 = 6ar^3 where a = first term and r = common ratio
Divide by a:
r + r^2 = 6r^3
6r^3 - r^2 - r = 0
r(6r^2 - r - 1) = 0
r(3r + 1)(2r - 1) = 0
So the 2 possible values of r
= -1/3 and 1/2.
i) The common ratio is positive so it must be 1/2.
Second term ar = 8
1/2 a = 8
a = 16.
So the first 6 terms are:
16, 8, 4, 2, 1, 1/2.
For

to be continuous at

, you need to have the limit from either side as

to be the same.


If

and

, then the limit from the right would be

, so the answer to part (1) is no, the function would not be continuous under those conditions.
This basically answers part (2). For the function to be continuous, you need to satisfy the relation

.
Part (c) is done similarly to part (1). This time, you need to limits from either side as

to match. You have


So,

and

have to satisfy the relation

, or

.
Part (4) is done by solving the system of equations above for

and

. I'll leave that to you, as well as part (5) since that's just drawing your findings.