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Ilya [14]
3 years ago
11

Rick has a collection of 6 video games. He lets his best friend borrow 2/6 of his video game collection. Write two fractions equ

ivalent to this number. Explain how you can came up with the fractions.
Mathematics
1 answer:
torisob [31]3 years ago
6 0
Both 2 and 6 are divisible by 2, so you would divide them by 2 and your fraction would be reduced to 1/3. You would get that answer by simply reducing the fraction.
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The crowd at a music concert is estimated to be 14,000 people. The exact attendance is 10,528 people. What is the percent error?
Dmitriy789 [7]

Answer:

32.9%

Step-by-step explanation:

14,000-10,528=3,472

3,472/10,528=0.32978723

Idk what your supposed to round to, but I put 32.9%

6 0
3 years ago
PLEASE HELP I GIVE THANKS
ololo11 [35]
The answer would be B because it crosses the X axis closer to the 0,0 than the original line
5 0
3 years ago
Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
ch4aika [34]

Answer:

\ln x+\frac{1}{3}\ln (x^2+1)

Step-by-step explanation:

Consider the given expression is

\ln (x\sqrt[3]{x^2+1})

We need to rewrite the expression as a sum,difference,or multiple of logarithms.

\ln (x(x^2+1)^{\frac{1}{3}})        [\because \sqrt[n]{x}=x^{\frac{1}{n}}]

Using the properties of logarithm we get

\ln x+\ln (x^2+1)^{\frac{1}{3}}         [\because \ln (ab)=\ln a+\ln b]

\ln x+\frac{1}{3}\ln (x^2+1)        [\because \ln (a^b)=b\ln a]

Therefore, the simplified form of the given expression is \ln x+\frac{1}{3}\ln (x^2+1).

6 0
3 years ago
Paco deconstructs this isosceles trapezoid to find the area.
Lina20 [59]
It would be the second one!!!
6 0
3 years ago
Read 2 more answers
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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