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Scrat [10]
2 years ago
14

Can you please factor (5n^2+10xn)(2n-3) all of the way down? (worth 50 pts)

Mathematics
2 answers:
Dovator [93]2 years ago
5 0

Answer:

n((2n+3)(5n+2x))

Step-by-step explanation:

that is the step by step solution

Oxana [17]2 years ago
4 0

Answer:

Step-by-step explanation:

I can help

Step 1

(5n^2+10xn)(2n-3)  Factorise

Step 2

5n^2+10xn factor

5n(n+2x)

5n(n+2x)(2n-3)

Answer

5n(n+2x)(2n-3)

Hope this helps

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Answer:

Your Answer would be C: $37.95

Step-by-step explanation:

Take 3.45 Multiply by 11 And get your answer

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3 years ago
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Which set of numbers is arranged in order from least to greatest?
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The answer is:  [C]:  -0.7, ⅕, 0.35, ⅔ .
________________________________________
Explanation:
_________________________________________
<span>
Note that in this correct Answer choice "C" given, we have the following arrangement of numbers:
_____________________________________________________
   </span>→ -0.7, ⅕, 0.35, ⅔ ; 
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We are asked to find the "Answer choice" (or, perhaps, "Answer choices?") given that show a set of numbers arranged in order from "least to greatest"; that is, starting with a value that is the smallest number in the arrangement, and sequentially progressing, in order from least to greatest, with the largest (greatest) number in the arrangement appearing as the last number in the arrangement.
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Note the EACH of the 4 (four) answer choices given consists of an arrangement with ONLY one negative number, "- 0.7".  Only TWO of the answer choices—Choices "B" and "C"—have an arrangement beginning with the number, "-0.7 ";  So we can "rule out" the "Answer choices: [A] and [D]".
________________________
Let us examine: Answer choice: [B]: <span>-0.7, 0.35, ⅕, ⅔ ; 
</span>_________________________
Note: The fraction, "⅕" = "2/10"; or, write as: 0.2 .
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          The fraction, "⅔" = 0.6666667 (that is 0.6666... repeating; so we often               see a "final decimal point" rounded to "7" at some point.
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Through experience, one will be able to automatically look at these 2 (two) fractions and immediately know their "decimal equivalents".
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Otherwise, one can determine the "decimal form" of these values on a calculator by division:
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→ ⅕ = 1/5 = 1 ÷ 5 = 0.2
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→ ⅔ = 2/3 = 2 ÷ 3 = 0.6666666666666667
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For Answer choice: [B], we have:
______________________________
→   -0.7, 0.35, ⅕, ⅔ ; 
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→ So, we can "rewrite" the arrangement of "Answer choice [B]" as:
___________________________________________
    →  -0.7, 0.35, 0.2, 0.666666667 ;
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    → And we can see that "Answer choice: [B]" is INCORRECT; because
"0.2" (that is, "⅕"), is LESS THAN "0.35".  So, "0.35" should not come BEFORE "⅕" in the arrangement that applies correctly to the problem.
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Let us examine: Answer choice: [C]:  -0.7, ⅕, 0.35, 0.666666667 .
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→ Remember from our previous— and aforementioned—examination of "Answer Choice: [B]" ; that:
____________________________ 
→ ⅕ = 0.2 ;   and:
→ ⅔ = 0.666666667
_______________________
So, given:
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→ Answer choice: [C]: -0.7, ⅕, 0.35, ⅔ ; 
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→ We can "rewrite" this given "arrangement", substituting our known "decimal values for the fractions:
______________________________
→ Answer choice: [C]: -0.7, 0.2, 0.35, 0.666666667 ;
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→ As mentioned above, this sequence starts with "-0.7", which is the ONLY negative number in the sequence; as such, the next positive number is correct.  Nonetheless, "0.2" (or, "(⅕") is the next number in the sequence, and is greater than "-0.7". The next number is "0.35. "0.35" is greater than "⅕" (or, "0.2"). Then next number is "(⅔)" (or, "0.666666667").
   "(⅔)"; (or, "0.666666667") is greater than 0.35.
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This set of numbers: "-0.7, ⅕, 0.35, ⅔" ; is arranged in order from least to greatest; which is "Answer choice: [C]: -0.7, ⅕, 0.35, ⅔" ; the correct answer.
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Answer:

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Step-by-step explanation:

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goldfiish [28.3K]
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Three friends shared 5/6 of a pizza equally. What fraction of the whole pizza did each friend get?
Ymorist [56]

Answer:

<em><u>5/18</u></em>

Step-by-step explanation

when you divide 5/6 by 3 you multiply 5/6 by 1/3 and you get 5/18!

I hope this helps!

4 0
3 years ago
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