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3 years ago

Can you please factor (5n^2+10xn)(2n-3) all of the way down? (worth 50 pts)

Mathematics

2 answers:

Dovator [93]3 years ago

5 0

Answer:

n((2n+3)(5n+2x))

Step-by-step explanation:

that is the step by step solution

Oxana [17]3 years ago

4 0

Answer:

Step-by-step explanation:

I can help

Step 1

(5n^2+10xn)(2n-3) Factorise

Step 2

5n^2+10xn factor

5n(n+2x)

5n(n+2x)(2n-3)

Answer

5n(n+2x)(2n-3)

Hope this helps

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2 years ago

Which are equivalent expressions?

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Answer:

Which are equivalent expressions?

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3 years ago

a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei

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Answer:

The weight of a small box = 13.5 kg

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Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) = 5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) = 3 n

Here, 3 large boxes + 5 small boxes = of 123 kilograms

⇒ 5 m + 3 n = 123 .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) = 2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) = 12 n

Here, 12 large boxes + 2 small boxes = 249 kilograms

⇒ 2 m+ 12 n = 249 .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5 m + 3 n = 123 x (2)

2 m+ 12 n = 249 x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

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So, 5 m = 123 -3 (18.5) = 123 - 55.5 = 67.5

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