Common difference d when The first term of an arithmetic sequence is 5, and the tenth term is 13 is 
Step-by-step explanation:
The first term a₁ = 5
The tenth term a₁₀ = 13
Find Common difference d=?
The formula used for arithmetic sequence is:
where aₙ = nth term
a₁= 1st term
d= common difference
Finding d:
So, Common difference d when The first term of an arithmetic sequence is 5, and the tenth term is 13 is
Keywords: arithmetic sequence
Learn more about arithmetic sequence at:
#learnwithBrainly
Answer: 2(7x + 3y + 4) [unsimplified] or 14x + 6y + 8 [simplified]
Step-by-step explanation: The perimeter of a parallelogram is 2 * (the two sides.)
Adding 5x + 4 and 2x + 3y, we get 7x + 3y + 4 by combining like terms in the x terms.
Now, we multiply by 2. This is 2(7x + 3y + 4) or 14x + 6y + 8
66 quarters and 28 dimes.
It took some time, but it is easy if you put it in an algebraic equation.
Answer:
54.3
Step-by-step explanation:
substitute the given values for v and w into the expression
(8.1 × 3 ) + (7.5 × 4 )
= 24.3 + 30 = 54.3
Answer:
1) 199
2) 899
Step-by-step explanation:
1)
The 2-digit number is the number formed from unit-digit and ten-digit
∵ The greatest digit is 9
→ To form the greatest 2-digit number use 9 as ten-digit and unit-digit
∴ The greatest 2-digit number is 99
The 3-digit number is the number formed from unit-digit, ten-digit, and hundred-digit
∵ The smallest digit is 0
→ To form the smallest 3-digit number use 0 as ten-digit and unit-digit,
we can not use 0 for the hundred-digit so use 1 as hundred-digit
∴ The smallest 3-digit number is 100
∵ The sum of them = 99 + 100
∴ Their sum is 199
2)
→ To form the greatest 3-digit number use 9 as hundred-digit, ten-digit,
and unit-digit
∴ The greatest 3-digit number is 999
∵ The smallest 3-digit number is 100
∵ The difference between them = 999 - 100
∴ The difference between them = 899
