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Dmitriy789 [7]
3 years ago
5

Find the gcf of 12,30,72

Mathematics
1 answer:
kvv77 [185]3 years ago
7 0

Answer: 6


Step-by-step explanation:

12 = 2^2 • 3

30 = 2 • 3 • 5

72 = 2^3 • 3^2


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Which is the quotient of 15 divided 4? 4/15, 2 2/3, 3 3/4, 4 4/15
Monica [59]

Answer:

its 3 3/4 or in decimal form 3.75

Step-by-step explanation:

15 divided by 4 gives you that answer

7 0
3 years ago
Is the ordered pair (0.5, 8.5) a solution to the following equations?
diamong [38]

Answer:

It's yes

Step-by-step explanation:

6 0
3 years ago
What three consecutive even numbers add up to 102?
Daniel [21]
So first you have to understand what consecutive numbers are.
Consecutive numbers are numbers like 4, 6, 8, 10, or 16, 18, 20. 

So let's set up an equation, using x as the first consecutive number. 
x + x + 2 + x + 4 = 102
Then simplify:
3x + 6 = 102
Subtract 6 from both sides.
3x = 96
Divide 3 on both sides:
x = 32

So the first number is 32, which means the other 2 numbers are 34, and 36. 
To check our answer, let's put the numbers in the equation.

32 + 32 + 2 + 32 + 4 = 102
Yep! That's correct.

The answer is 32, 34, and 36.

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
6 0
3 years ago
Read 2 more answers
Use binomial expansion to solve each exercise. (a) Find the coefficient of xy19 in (3x − 2y) 20.(b) Give a formula for the coeff
pishuonlain [190]

9514 1404 393

Answer:

  (a) -29,884,416

  (b) C(n,(n -k)/2) . . . where C(n,k) = n!/(k!(n-k)!) and k ∈ ℕ

Step-by-step explanation:

(a) The coefficient of the k-th term of the expansion is ...

  C(20,k)(3x)^(20-k)(-2y)^k

For k=19, this is ...

  19(3x)(-2y)^19 = -29,884,416xy^19

The coefficient of the term is -29,884,416.

__

(b) The p-th term of the expansion of (x +1/x)^n is ...

  C(n,p)(x^(n-p)(1/x)^p = C(n,p)(x^(n-2p))

For some exponent k of x, the value of p will be ...

  k = n -2p

  p = (n -k)/2

Then the coefficient of x^k will be C(n, (n-k)/2), where C(n, x) = n!/(x!(n-x)!).

You will notice that there will only be a term x^k for k having the same parity as n.

5 0
3 years ago
Write the quadratic function in standard form.<br><br> y = (x - 2)^2 + 4
Mrrafil [7]

Answer:

y = x^2 - 4x + 8

Step-by-step explanation:

<u>Step 1:  Factor the (x - 2)^2</u>

y = (x - 2)^2 + 4

y = x^2 - 4x + 4 + 4

y = x^2 - 4x + 8

Answer:  y = x^2 - 4x + 8

8 0
3 years ago
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