The value of the given integral is (3x+2)^2^1 /63 +c
=
=1/3*{(3x-20)^21}/21 +c
=1/63 *(3x-21)^21 +c
=d/dx {1/3*(3x-2)^21}/21 +c
=3/3 *{21(3x-2)}/21 +c
Let u=3x-2
du= 3dx
=
=1/3
=(3x+2)^2^1 /63 +c
For more information about integrals, visit
brainly.com/question/22008756
#SPJ4
Answer:
36% of 240
=36/100*240
=6640/100
=86.4
Step-by-step explanation:
Answer:
For this case is the rectangle is dilated a factor of 2.2 we assume that the expansion is in all the dimensions so then the new length and width are:
Step-by-step explanation:
The area of a rectangle is given by
For this case is the rectangle is dilated a factor of 2.2 we assume that the expansion is in all the dimensions so then the new length and width are:
And the area would be (2.2)^2 times the initial area since is defined as
Answer:
ok cool
Step-by-step explanation:
Answer:
Step-by-step explanation:
We require to create 2 equations with the repeating digit (6) after the decimal point.
let x = 0.166.... ( multiply both sides by 10 and 100 )
10x = 1.66.... → (1)
100x = 16.66..... → (2)
Subtract (1) from (2) eliminating the repeating decimal
90x = 15 ( divide both sides by 90 )
x = =
Thus
0.166...... =