Question

In the triangle below, what is the length of the side opposite the 60 angle?

Answer 1

Answer with explanation:

In the given right triangle

 $\sin 60^{\circ}=\frac{\text{Perpendicular}}{\text{Hypotenuse}}\\\\ \frac{\sqrt{3}}{2}=\frac{\text{Perpendicular}}{2\sqrt{3}}\\\\ \text{Perpendicular}}=2\sqrt{3} \times\frac{\sqrt{3}}{2}\\\\\text{Perpendicular}}=\sqrt{3} \times\sqrt{3} \\\\\text{Perpendicular}}=3$

→Side opposite to 60° angle = 3 units

Option C : 3 Units

Answer 2

It is 3 cause i got it wrong and that was the right anser