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asambeis [7]
2 years ago
6

Evaluate the indefinite integral. (use c for the constant of integration. ) int (3x - 2)**20 dx

Mathematics
1 answer:
qaws [65]2 years ago
8 0

The value of the given integral is (3x+2)^2^1 /63 +c

=  1/3\int\limits^a_b {(3x-2)^2^0} \, dx

=1/3*{(3x-20)^21}/21 +c

=1/63 *(3x-21)^21 +c

=d/dx {1/3*(3x-2)^21}/21 +c

=3/3 *{21(3x-2)}/21 +c

Let u=3x-2

du= 3dx

=\int\limits^a_b {(3x-2)^2^0} \, dx = 1/3\int\limits^a_b {(3x-2)^2^0 dx} \, 3dx

=1/3\int\limits^a_b {u^2^0} \, du  =1/63 * u^2^1

=(3x+2)^2^1 /63 +c

For more information about integrals, visit

brainly.com/question/22008756

#SPJ4

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