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gregori [183]
2 years ago
8

UNIT 2 lesson 12 polygons and quadrilaterals unit test part one!!!!!!!

Mathematics
1 answer:
Sholpan [36]2 years ago
4 0

The coordinates of point P is the location of point P in the coordinate plane

The coordinates of point of P is (a + c, b)

<h3>How to determine the coordinate of P</h3>

From the complete question (see attachment), point P and the coordinate (a,b) are on the same horizontal line.

This means that the y-coordinate of point P is b

To determine the x-coordinate of point P, we make use of the following equation

x = a+ c

This is so because, the horizontal line from coordinate (a,b) to line P has the same length as line 0c.

So, the coordinates of point of P is:

P = (a + c, b)

Hence, the coordinates of point of P is (a + c, b)

Read more about coordinates at:

brainly.com/question/7243416

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80 is 5% of what number?​
nikklg [1K]

Answer:

1600

Step-by-step explanation:

1600 x 0.05 = 80

or

80 / .05 = 1600

3 0
2 years ago
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8 Mineral Hardness Common object Diamond 10 Corundum 9 Topaz Quartz 7 Feldspar 6 Steel file (6.5) Apatite 5 Glass (5.5) Fluorite
adoni [48]

Answer:

feldspar, because it has a higher number then gypsum and apatite, and it can be scratched by quartz because it has a lower number.

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2 years ago
f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
Quadrilateral LMNO is a rectangle. Find MN.
Cloud [144]
(4x-1)=(5x-8)
x=7

4(7)-1= 27

5(7)-8= 27

So the answer is 27

<span>MN = 27</span>

3 0
3 years ago
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If a transformation moves points only up or down, how do the coordinates of the point change? What can you conclude about the co
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