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krok68 [10]
3 years ago
10

he plates of a parallel - plate capacitor are maintained with constant voltage by a battery as they are pulled apart. What happe

ns to the strength of the electric field between the plates during this process?
Physics
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

The strength of the electric field between the plates of the capacitor decreases during this process.

Explanation:

The strength of electric field between the plates of a capacitor is given as

E = (V/d)

where V = potential difference across the plates of the capacitor

And d = distance between the two places

So, if the potential difference across the plates of the capacitor stays constant, the electric field strength varies inversely as the distance between the plates.

Therefore, as the plates of the capacitor are pulled apart, with distance between them increasing (with constant voltage maintained across the plates), the strength of the electric field between the plates decreases.

Hope this Helps!!

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Answer:

im not 100 percent but its probably 2 turtles 20m apart

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3 years ago
How much time does it take a power drill accelerating at 64.3 rad/s2 to achieve
Diano4ka-milaya [45]

Answer;

= 0.244 seconds

Explanation;

500 rpm is equivalent to; 1500 × 2π radians per minute

   = 9424.8 rad/minute  

To get revolutions per second we divide by 60

  = 9424.8/60  

   = 157.08 radians per second.  

Then we divide by 64.3 rad/s^2 to get time;

    = 157.08/64.3

     = 0.244 seconds.

7 0
3 years ago
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Oceanic water particles mainly move in circles; is this movement greater on the ocean's surface or below the surface? Explain yo
goblinko [34]
I think that the oceanic water particles mainly move in circles greater in the oceans surface because of how big the waves can be and how wind and air impact the motion. The water particles move more on the surface because of the other factors that impact it such as people, wind, air, etc...
5 0
3 years ago
Illustrate the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum bob to one sid
agasfer [191]

Answer:

Energy transforms from Potential energy to (Kinetic Energy+heat+air drag) to potential energy. The bob comes to rest as it loses its energy due to the influence of the factors from the surroundings. The bob's energy is lost eventually and no, this happening is not a violation of the law of energy conservation.

Explanation:

  • For the illustration please refer to the figure attached herewith.
  • The bob is given some energy in the form of potential energy at the beginning and after it is released it swings back and forth interchanging energy between the potential to kinetic and keeping the total of its energy constant.
  • Only in the ideal conditions (no friction loss at the pivotal point, no air drag) the conditions described just above happen to exist. Else, where all the resistances are available: in the practical scenario, some energy gets dissipated to the environment via these factors making the total energy no longer a constant.
  • As a result of this, both its potential and kinetic energy also get reduced illustrating a gradual reduction of the height the bob would rise and the speed it would swing with.
  • The energy distribution, in this case, happens to be like this: Bob's total energy - lost energy = potential energy + kinetic energy.
  • This lost energy is not a miracle it is nature that some energy is transformed into some other form hence this happening is not a violation of the law of energy conservation.
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#SPJ4

4 0
2 years ago
Pls someone I need it urgently and explain Solving and explanation so I can understand Thank you
Temka [501]

Answer:

   f = 6.37 Hz,       T = 0.157 s

Explanation:

The expression you have is

       y = 5 sin (3x - 40t)

this is the equation of a traveling wave, the general form of the expression is

      y = A sin (kx - wt)

where A is the amplitude of the motion, k the wave vector and w the angular velocity

Angle velocity and frequency are related

         w = 2π f

         f = w / 2π

from the equation w = 40 rad / s

        f = 40 / 2π

        f = 6.37 Hz

frequency and period are related

       f = 1 / T

       T = 1 / f

       T = 1 / 6.37

       T = 0.157 s

4 0
3 years ago
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