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alexdok [17]
2 years ago
15

A glass rod with yellow crosses on it touches a sheet of silk covered with negative signs on it. the sheet of silk is sticking t

o the glass rod in several places. use the drop-down menu to answer the question. a student is going to produce static charge in a glass rod by rubbing it with a piece of silk. which method of transferring charge does this image illustrate?
Physics
1 answer:
forsale [732]2 years ago
5 0

The image as shown here can here can be used to describe charging by induction.

<h3>What is a charge?</h3>

A charge may be positive or negative. One of the methods of transferring a charge is by induction.

In this case, an objects induces an opposite charge on a material.  The image as shown here can here can be used to describe charging by induction.

Learn more about charging by induction:brainly.com/question/10254645

#SPJ4

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3 years ago
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

brainly.com/question/6947486

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8 0
2 years ago
A 4.0-m-diameter playground merry-go-round, with a moment of inertia of
HACTEHA [7]

Answer:

7.1 ms⁻¹

Explanation:

d = diameter of merry-go-round = 4 m

r = radius of merry-go-round = \frac{d}{2} =  \frac{4}{2} = 2 m

I = moment of inertia = 500 kgm²

w_{i} = angular velocity of merry-go-round before ryan jumps = 2.0 rad/s

w_{f} = angular velocity of merry-go-round after ryan jumps = 0 rad/s

v = velocity of ryan before jumping onto the merry-go-round

m = mass of ryan = 70 kg

Using conservation of angular momentum

Iw_{i} - m v r = (I + mr^{2})w_{f}

(500)(2.0) - (70) v (2) = (I + mr^{2})(0)

1000 = 140 v

v = 7.1 ms⁻¹

5 0
3 years ago
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