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3 years ago

6

A charged particle is known as a(n)

1 answer:

Andreas93 [3]3 years ago

3 0

The answer is plasma

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Which of the following statements describes electric fields?

tia_tia [17]

C)Electric Charges Produce Electric Fields

7 0

3 years ago

Read 2 more answers

You place an object 30.0 cm from a concave mirror of 15.0 cm focal length. The object is 1.8 cm tall. Find the image position an

Softa [21]

Answer:30 cm

Explanation:

Given

object distance $u=30\ cm$

focal length of concave mirror $f=15\ cm$

height of object $h_o=1.8\ cm$

Using mirror formula

$\Rightarrow \frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\Rightarrow \frac{1}{v}=\frac{1}{15}-\frac{1}{30}$

$\Rightarrow \frac{1}{v}=\frac{2-1}{30}$

$\Rightarrow v=30\ cm$

and magnification is

$\Rightarrow m=\frac{-v}{u}=\frac{h_i}{h_o}$

$\Rightarrow \frac{-30}{30}=\frac{h_i}{1.8}$

$\Rightarrow h_i=-1.8\ cm$

So height of object is same as of object .

Position :image is formed at the spot where object is placed.

4 0

3 years ago

What is the kinetic energy of a toy truck with a mass of 0.75 kg and a velocity of 4 m/s? (Formula: )

jeyben [28]

<span>The answer is 6 Joules. The kinetic energy (KE) of an object is the product of half of the mass (m) of the object and the square of its velocity (v²): KE = 1/2m*v². We know that m = 0.75 kg and that v = 4 m/s. Therefore, KE = 1/2 * 0.75 kg * (4 m/s)² = 1/2 * 0.75 kg * 16 m²/s² = 6 kg*m²/s² = 6 J.</span>

6 0

3 years ago

Read 2 more answers

A light source shines light consisting of two wavelengths, λ1 = 540 nm (green) and λ2 = 450 nm (blue), on two slits separated by

densk [106]

Answer:

The maximun distance is $z_1 = z_2 = 0.0138m$

Explanation:

From the question we are told that

The wavelength are $\lambda _ 1 = 540nm (green) = 540 *10^{-9}m$

$\lambda_2 = 450nm(blue) = 450 *10^{-9}m$

The distance of seperation of the two slit is $d = 0.180mm = 0.180 *10^{-3}m$

The distance from the screen is $D = 1.53m$

Generally the distance of the bright fringe to the center of the screen is mathematically represented as

$z = \frac{m \lambda D}{d}$

Where m is the order of the fringe

For the first wavelength we have

$z_1 = \frac{m_1 (549 *10^{-9} * (1.53))}{0.180*10^{-3}}$

$z_1=0.00459m_1 m$

$z_1= 4.6*10^{-3}m_1 m ----(1)$

For the second wavelength we have

$z_2 = m_2 \frac{450*10^{-9} * 1.53 }{0.180*10^{-3}}$

$z_2 = 0.003825m_2$

$z_2 = 3.825 *10^{-3} m_2 m$ ----(2)

From the question we are told that the two sides coincides with one another so

$zy_1 =z_2$

$4.6*10^{-3}m_1 m = 3.825 *10^{-3} m_2 m$

$\frac{m_1}{m_2} = \frac{3.825 *10^{-3}}{4.6*10^{-3}}$

Hence for this equation to be solved

$m_1 = 3$

and $m_2 = 4$

Substituting this into the equation

$z_1 = z_2 = 3 * 4.6*10^{-3} = 4* 3.825*10^{-3}$

Hence $z_1 = z_2 = 0.0138m$

7 0

3 years ago

A passenger walks from one side of a ferry to the other as it approaches a dock.Passenger's velocity is 1.55 m/s due north relat

victus00 [196]

Answer: $\theta =33.22^{\circ}$

Explanation:

Given

Velocity of Passenger w.r.t to Ferry

$v_{pf}=v_p-v_f=1.55\hat{j}$ -------1

Velocity of Passenger w.r.t to water

$v_{pw}=v_p-v_w=4.5\left ( -\hat{i}+\hat{j}\right )$ --------2

Subtract 2 from 1

$v_f-v_w=-4.5\hat{i}+2.95\hat{j}$

(b)direction

$tan\theta =\frac{2.95}{4.5}=0.655$

$\theta =33.22^{\circ}$ North of west

5 0

4 years ago