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Zarrin [17]
3 years ago
7

Four times the square of a certain number increased by 6 times the number equals 108.find the number

Mathematics
2 answers:
mash [69]3 years ago
7 0
Hello there.
<span>
Four times the square of a certain number increased by 6 times the number equals 108.find the number
</span>
x = 4.5
x = -6 
slamgirl [31]3 years ago
5 0
To effectively determine the correct answer, it would be helpful to write this into an algebraic expression. We let x as the number. We do as follows:

<span>Four times the square of a certain number increased by 6 times the number equals 108.

4x^2 + 6x = 108

The numbers can be either of the following since the equation generated was a quadratic equation which has two roots.
x = 4.5
x = -6 </span>
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sergij07 [2.7K]

thanks for the points dude

4 0
2 years ago
Using the following image, solve for SR. Look at the image closely.
iren [92.7K]

Step-by-step explanation:

I assume

SR = 2x + 23

RQ = x + 21

if that is true, then the situation is completely simple :

14 = (2x + 23) + (x + 21) = 3x + 44

3x = -30

x = -10

SR = 2×-10 + 23 = -20 + 23 = 3

RQ = -10 + 21 = 11

4 0
2 years ago
Read 2 more answers
Show the work for answer, if the area of a pizza is 153.94 square inches, find the length of its diameter
TEA [102]

Answer:

14 inch

Step-by-step explanation:

A = πr^2

153.94 = π * r^2

153.94/π = 49.001 = r^2

√49.001 = r = 7

radius * 2 = diameter

7 * 2 = 14 inch diameter

7 0
2 years ago
Consider the differential equation: y′′−8y′=7x+1. Find the general solution to the corresponding homogeneous equation. In your a
Margaret [11]

Answer:

yp = -x/8

Step-by-step explanation:

Given the differential equation: y′′−8y′=7x+1,

The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)

First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;

y′′−8y′=0

The auxiliary equation will give us;

m²-8m = 0

m(m-8) = 0

m = 0 and m-8 = 0

m1 = 0 and m2 = 8

Since the value of the roots are real and different, the complementary solution (yc) will give us

yc = Ae^m1x + Be^m2x

yc = Ae^0+Be^8x

yc = A+Be^8x

To get yp we will differentiate yc twice and substitute the answers into the original DE

yp = Ax+B (using the method of undetermined coefficients

y'p = A

y"p = 0

Substituting the differentials into the general DE to get the constants we have;

0-8A = 7x+1

Comparing coefficients

-8A = 1

A = -1/8

B = 0

yp = -1/8x+0

yp = -x/8 (particular integral)

y = yc+yp

y = A+Be^8x-x/8

3 0
2 years ago
Simplify (2sq root 5-4) (3sq root 5-2)
tatuchka [14]

Answer:

2√5-4(3√5-2)

6√25-4√5-12√5+8

6(5)-16√5+8

30+8-16√5

38-16√5

7 0
3 years ago
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