Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
Step 1
<u>Find the slope of the given line</u>
we have

Isolate the variable y
Subtract
both sides


Divide by
both sides

the slope of the given line is

Step 2
Find the equation of the line that passes through the point
and is parallel to the given line
we know that
if two lines are parallel, then their slopes are equal
The equation of the line into point-slope form is equal to

we have

substitute in the equation


or 
therefore
<u>the answer is</u>
or

Use percentage multipliers:
$28/0.8 = $35
The original price of the set is $35.
Hope This Helps!
Randomization is important to ensure that both groups are roughly equivalent regarding students’ preparedness, anxiety levels, and study skills.
<h3>What is randomization in an experiment?</h3>
Randomization is when subjects in an experiment are placed in either the control group or the treatment group without any structure. They are placed in either groups randomly. The purpose of randomization is to ensure that subjects in either group are homogenous.
To learn more about randomization, please check: brainly.com/question/20629933
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<h2>
Step-by-step explanation:</h2>
As per the question,
Let a be any positive integer and b = 4.
According to Euclid division lemma , a = 4q + r
where 0 ≤ r < b.
Thus,
r = 0, 1, 2, 3
Since, a is an odd integer, and
The only valid value of r = 1 and 3
So a = 4q + 1 or 4q + 3
<u>Case 1 :-</u> When a = 4q + 1
On squaring both sides, we get
a² = (4q + 1)²
= 16q² + 8q + 1
= 8(2q² + q) + 1
= 8m + 1 , where m = 2q² + q
<u>Case 2 :-</u> when a = 4q + 3
On squaring both sides, we get
a² = (4q + 3)²
= 16q² + 24q + 9
= 8 (2q² + 3q + 1) + 1
= 8m +1, where m = 2q² + 3q +1
Now,
<u>We can see that at every odd values of r, square of a is in the form of 8m +1.</u>
Also we know, a = 4q +1 and 4q +3 are not divisible by 2 means these all numbers are odd numbers.
Hence , it is clear that square of an odd positive is in form of 8m +1