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Svet_ta [14]
3 years ago
6

Find parametric equations for the tangent line to the curve of intersection of the paraboloid z = x2 + y2 and the ellipsoid 3x2

+ 2y2 + 4z2 = 21 at the point (−1, 1, 2). (Enter your answer as a comma-separated list of equations. Let x, y, and z be in terms of t.)
Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

x=-1-18 t,y=1+19 t,z=2-2 t

Step-by-step explanation:

We are given that

Equation of paraboloid

z=x^2+y^2

z-x^2-y^2=0

And equation of the ellipsoid

3x^2+2y^2+4z^2-21=0

We have to find the parametric equation for tangent line to the curve of the intersection of the paraboloid and ellipsoid at point (-1,1,2).

We have to find the normal at point (-1,1,2)

N_1=-2x\hat{i}-2y\hat{j}+\hat{k}

Normal at point (-1,1,2)

N_1=

N_2=6x\hat{i}+4y\hat{j}+8z\hat{k}

Normal at point (-1,1,2)

N_2=

We rescale and set N_2=

The tangent vector to the curve of intersection is given by

N_1\time N_2=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\2&-2&1\\-3&2&8\end{vmatrix}

N_1\times N_2=

Hence, the tangent line is given by

x=-1-18 t,y=1+19 t,z=2-2 t

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If you would like to know how much money will Gerold have at the end of 5 years, you can calculate this using the following steps:

1 year: $118 + 6% * $118 = 118 + 6/100 * 118 = 118 + 7.08 = $125.08
2 year: $125.08 + 6% * $125.08 = 125.08 + 6/100 * 125.08 = 125.08 + 7.50 = $132.58
3 year: $132.58 + 6% * $132.58 = 132.58 + 6/100 * 132.58 = 132.58 + 7.95 = $140.53
4 year: $140.53 + 6% * $140.53 = 140.53 + 6/100 * 140.53 = 140.53 + 8.43 = $148.96
5 year: $148.96 + 6% * $148.96 = 148.96 + 6/100 * 148.96 = 148.96 + 8.94 = $157.9

The correct result would be $157.9.
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Answer:

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Step-by-step explanation:

( 3 sqrt(3), 3)

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Taking the inverse tan of each side

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