Answer:
Function 1:
The starting point is (0,0.5)
As x increases, y increases
Function 2:
The starting point is (0,3)
As x increases, y decreases
Step-by-step explanation:
In order to find the starting point, we need to plug in x=0.


As we plug in increasing numbers into function#1, the y-value increases
As we plug in increasing numbers into function #2, the y-value is decreasing
Ln(xy) - 2x =0
slope of the tangent line = derivative of the function
[ln(xy)]' = [2x]'
[1/(xy)] [y + xy'] = 2
y + xy' = 2(xy)
xy' = 2xy - y =y(2x-1)
y' = y(2x-1)/x
Now use x = -1 to find y and after to find y'
ln(xy) = 2x
x=-1
ln(-y) =-2
-y = e^-2
y = - e^-2
y' = [-e^-2][2(-1)-1]/(-1) = [e^-2](-2-1)= [e^-2](-3) = - 3e^-2
Answer: option 6. from the list
Answer:
0
Step-by-step explanation:
There is no slope because it is a strait vertical line.