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iogann1982 [59]
2 years ago
8

Find the value of each variable. 105° 86° 106°/2°

Mathematics
1 answer:
forsale [732]2 years ago
5 0

Answer:

z = 74 degrees

y = 115 degrees

Step-by-step explanation:

Explanation in the attachment.

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The table of values represents an exponential function f(x).
Ostrovityanka [42]

Answer:

-3.98 (nearest hundredth)

Step-by-step explanation:

The average rate of change of function f(x) over the interval a ≤ x ≤ b is given by:

\dfrac{f(b)-f(a)}{b-a}

Given interval:  -2 ≤ x ≤ 2

\implies a = -2

\implies b = 2

\implies f(a) = f(-2)=16

\implies f(b) =f(2)= \dfrac{1}{16}

Substituting the values into the equation:

\begin{aligned}\implies \textsf{rate of change} & =\dfrac{\frac{1}{16}-16}{2-(-2)}\\\\ & = \dfrac{-\frac{255}{16}}{4}\\\\ & = -\dfrac{255}{64}\\\\ & = -3.98\: \sf (nearest\:hundredth)\end{aligned}

7 0
2 years ago
What is -34 1/2 - 5 1/2
Verizon [17]

The answer is -40 because if you get rid of the negative sign and add instead of subtract... you get 40 so its like adding in the opposite direction.

3 0
3 years ago
Read 2 more answers
Prove that:<br><br>cos20°cos40°cos80°=1/8​
Naya [18.7K]

Answer:

see explanation

Step-by-step explanation:

Using the double angle identity for sine

sin2x = 2sinxcosx

Consider left side

cos20°cos40°cos80°

= \frac{1}{2sin20} (2sin20°cos20°)cos40°cos80°

= \frac{1}{4sin20} (2sin40°cos40°)cos80°

= \frac{1}{4sin20} (sin80°cos80° )

= \frac{1}{8sin20} (2sin80°cos80° )

= \frac{1}{8sin20} . sin160°

= \frac{1}{8sin20} . sin(180 - 20)°

= \frac{1}{8sin20} . sin20°

= \frac{1}{8} = right side , thus proven

7 0
2 years ago
Read 2 more answers
7 people are having dinner at a restaurant and decide to split the cheque evenly between them. If the check came to a total of $
DanielleElmas [232]

Answer:

The answer will be $54.5

Step-by-step explanation:

If 7 people slit $381.50 evenly, we will have

$381.50/7 = $54.5

7 0
3 years ago
Can you Factor this equation?<br><br> 20mn - 15n
Greeley [361]
You can factor out a 5n to get
5n(4m-3)
7 0
3 years ago
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